题目Find an equation of the line: parallel to the line x-2y-1=0 passing through (0,0) 相关知识点: 试题来源: 解析 y= 12x 结果一 题目 Find an equation of the line: parallel to the line x-2y-1=0 passing through (0,0) 答案相关推荐 1Find an equation of the line: parallel t...
题目Find an equation of the line: parallel to the line x-2y-1=0 passing through (0,0) 相关知识点: 试题来源: 解析 y= 12x 结果一 题目 Find an equation of the line: parallel to the line x-2y-1=0 passing through (0,0) 答案 1 y= 2 C相关推荐 1Find an equation of the line...
To find the equation of the line parallel to the line 3x−4y+2=0 and passing through the point (2,3), we can follow these steps: Step 1: Identify the slope of the given lineFirst, we need to convert the equation of the given line into the slope-intercept form y=mx+c, where ...
Write the slope-intercept form of the equation of the line passing through the point (5,1) and parallel to the line y = -4x - 2. Write the equation of the line in slope-intercept form that goes through the given point and is parallel (4...
The equation of the line by the point P=(0,b) parallel to the vector v=[1,m] is given by r(t)=r0+tv where r0=P 1.2 parametric equation of a line A line with vector equation r(t)=r0+tv where r0=[0,b] and v=[1,m] can also be written as follows [x(t),y(t...
1. Give the equation of the line parallel to Line 1 which passes through (-2,-9): ()2. Give the equation of the line perpendicular to Line 1 which passes through (-2,-9): () 相关知识点: 试题来源: 解析 1. y=35x-(39)52. y=-35x-(37)3...
百度试题 结果1 题目Write down the equation of the line that is parallel to y =÷x +3 and2passes through (0, -1)y=1/2X-1 相关知识点: 试题来源: 解析 y= 反馈 收藏
Find the equation of a line parallel to the line3x−4y+2=0and passing through the point.(−2,5). View Solution Find the equation of the line parallel to the y-axis and 3 units to the right of it. View Solution Find the equation of a line parallel to the line x+2y-1=0, wh...
Step 3: Write the vector equation of the line parallel to the given lineSince we need to find a line parallel to the given line, we can use the same direction vector b but with a different point a. Let's denote the new point as (α,β,γ). Thus, the vector equation of the line...
The equation of the graph of a straight line can be written in point-slope form, or slope-intercept form. The slope-intercept form of the equation is {eq}y=mx+b {/eq} where m is the slope of the line, and b is the y-intercept of the line. The y-...