(2)ⅱ -5x+3y+12z=12 (3)ⅱ -y+z=3 {many vector forms exist} 反馈 收藏
12年级向量与微积分 Cartesian Equation 12年级向量与微积分 Cartesian Equation of a plane #加拿大高中留学 #美国高中留学 #微积分 - 北美高中数学陈老师于20240315发布在抖音,已经收获了378个喜欢,来抖音,记录美好生活!
The meaning of CARTESIAN EQUATION is an equation of a curve or surface in which the variables are the Cartesian coordinates of a point on the curve or surface.
31 0 10:00 App P3 7.8 Vectors _ Cartesian Equation of a Line in 3D 81 0 04:58 App P3 7.2 Vector Equation of a Line _ Example 1 7 0 07:41 App P3 7.0.8 Vectors _ Example 2 22 0 05:45 App P3 7.15 Intersection of a Line and Plane 18 0 09:03 App P3 7.9 Vectors - Equatio...
The equation of a plane in three-dimensional space is defined by a normal vector and known points on the plane. A vector is a physical quantity, and in addition to its size, it also has a direction. The equation of the plane can be expressed either in cartesian form or vector form. ...
The Cartesian or scalar equation of a plane in ℝ3 has the form: A⋅x +B⋅y + C⋅z + D = 0, where A, B, C, D are real-valued parameters. The vector A,B,C is normal (perpendicular) to the plane.Change...
Find the vector and the Cartesian form of the equation of the plane containing two lines: vecr=hati+2hatj-hatk+lamda(2hati+3hatj+6hatk) and vecr= 3hati+3hatj-
vec rcdot(s+t) hat i+(2+t) hat j+(3s+2t) hat k=15 Put vec r=xhati+yhatj+zhatk In cartesian form, required equation is, (xhati+yhatj+zhatk)cdot[(s+t) hat i+(2+t) hat j+(3s+2t) hat k]=15 implies x(s+t)+y(2+t)+z(3s+2t)=15
百度试题 结果1 题目Find a Cartesian equation of the plane which passes through the point (1,1,1) and contains the line with equation (x-2)3= (y+4)1= (z-1)2.相关知识点: 试题来源: 解析 -10x-2y+16z=4 反馈 收藏
Plane is a surface containing completely each straight line, connecting its any points.General form of the equation of a planeAny equation of a plane can by written in the general formA x + B y + C z + D = 0where A, B and C are not simultaneously equal to zero.Equation...