The equation of tangent and normal can be evaluated just like any other straight line. But to find the gradient of tangents and normals to a curve, students will need the derivative. If the slope of the tangent to a curve y = f(x) at a point a is f'(a) (derivative of f(x) ...
Eq. of Tangent: y - y1= m(x - x1) calculate n = negative reciprocal of the above m; Eq. of Normal: y - y1= n(x - x1). Can you do the implicit differentiation? Upvote•0Downvote Add comment Report Still looking for help? Get the right answer, fast. ...
结果1 题目 Find the equation of the tangent line and the equation of the normal line drawn to the curve x^( 2/3)+y^( 2/3)=5 at the point (8,1). 相关知识点: 试题来源: 解析 y-1=-12(x-8)y-1=2(x-8) 反馈 收藏 ...
Solution Share Step 1 Need to find the equation of the tangent and the normal line to the curve y=2x+1 at x=4. First, find the deriv...View the full answer Step 2 Unlock Step 3 Unlock Step 4 Unlock Answer UnlockPrevious question Next qu...
网络切线方程式 网络释义 1. 切线方程式 英翻中 - 95年猫头鹰家族 - Yahoo!奇摩部落格 ... equation 方程式equation of tangent line切线方程式error 误差 ... tw.myblog.yahoo.com|基于 1 个网页
Find the point on the curve y = x sqrt(x) for which the tangent line to the curve is perpendicular to the line 4x + 5y+6 = 0. Find the equation of the normal line to the indicated curve at the given point: y = 3x - 2x^2 at (5, -35). ...
Learn how to find a normal line equation. Use a derivative and perpendicular slope of a tangent line to calculate the equation of the normal line...
Let the equation of the tangent line be y= -x +b. Substituting this into the equation of the circle: 2x^2- 2bx+b^2-4=0 . Since the line is tangent to the circle, we have △=(-2b)^2-4*2(b^2-4)=0 Solving for b: b =±2 2. So the equation of the tangent line is ...
equation of the line tangent 公式我们要找出直线与曲线相切的方程。 首先,我们需要知道切线的定义和性质,然后使用这些性质来找出切线的方程。 假设曲线方程为 y = f(x),切点为 (x0, f(x0))。 切线的斜率等于函数在该点的导数,即 f'(x0)。 所以,切线的方程可以表示为:y - f(x0) = f'(x0) ×...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...