Find the equation of a circle with center (4, 3) touching the circle x2+y2=1 View Solution The equation to the circle with centre (2,1) and touching the line 3x+4y=5 is View Solution The equation of the common
<p>To find the equation of a circle centered on the X-axis and passing through the points (6, 4) and (8, -4), we can follow these steps:</p><p><strong>Step 1: General Equation of Circle</strong> The general equation of a circle can be written as: \( x^2
These two extremities therefore have a significance partially independent of the choice of the origin on the unit circle. The operation leads to the introduction of a “pseudodilation” operator. Consider a function a : E → C, and let B be a structuring element. The pseudodilation δ : C...
The equation to find the area of a sector of a circle is given by A= (∏ ^2S)(360) where A is the area, r is the radius and s is the length of a side. Solve the formula for the value of the side, s. 相关知识点: 试题来源: 解析 s= (360A)(∏ r^2) 反馈 收藏 ...
{eq}A = \frac{1}{2}\int_{C}\left ( x \ dy - y \ dx \right ) {/eq} Answer and Explanation: The parametric equations of the circle of radius {eq}3 {/eq} are written as: {eq}\\\ x=3\cos\theta \\\ y=3\sin\theta {/...
6 =0, having the radius double of its radius. solution: given, circle equation: x 2 + y 2 + 4x – 8y – 6 =0 we know that the equation of the circle is x 2 + y 2 + 2gx + 2fy + c =0 from the given equation, the center point is (-2, 4) therefore, the radius of ...
Step 1: Understanding the Circle's EquationThe general equation of a circle with center (h,k) and radius r is given by:(x−h)2+(y−k)2=r2 Step 2: Center on the LineSince the center (h,k) lies on the line x−4y=1, we can express h in terms of k:h=4k+1 Step 3: ...
The center is (1,2) and since since the circle touches the x-axis , the radius is equal to 2. Hence, the equation is (x-1)^(2)+(y-2)^(2)=2^(2) or x^(2)+y^(2)-2x-4y+1=0
- If the center is below the line, r=2−k. For our case, since the circle can be either above or below the line, we can write:r=|k−2| Step 4: Write the Equation of the CircleThe general equation of a circle with center (0,k) and radius r is given by:x2+(y−k)2...
1. General Equation of a Circle: Again, we start with the general equation: (x−h)2+(y−k)2=r2 2. Setting the Center: Since the circle touches the y-axis at the origin (0, 0), the center must be on the line x=h where h is the radius. Thus, the center can be expressed...