Let the equation of the tangent line be y= -x +b. Substituting this into the equation of the circle: 2x^2- 2bx+b^2-4=0 . Since the line is tangent to the circle, we have △=(-2b)^2-4*2(b^2-4)=0 Solving for b: b =±2 2. So the equation of the tangent line is ...
【解析】Solution:(x-4)^2+(y-4)^2=160r(x-1)^2+ (y+1)^2=1 Method 1:Since the circle is tangent to both axes, the center ofthe circle is on the line.Solving5x-3y=8;x±y=0. x=4;y=4. =4arx=1;y=-1.Therefore the equation of the circle is(x -4)2+(y-4)^2=160r...
(xo,y)The equation of the tangent line passing through P isxxo+yyo=4.Since the tangent point is on the circle+y=4(1)Since Q(3, 0) is on the tangent line3xo=4(2)Solving(1) and(2), we get the coordinate of thegnot () tad(4/3,-(2√5)/3) .Teqioh agn i sx+2=4or-...
The equation of the tangent to the circle x^2+y^2=25 passing through (... 05:00 Consider the circles C(1)-=x^(2)+y^(2)-2x-4y-4=0andC(2)-=x^(2)+y^(2)+2... 06:27 a square is inscribed in the circle x^2 + y^2- 10x - 6y + 30 = 0. One ... 07:04Exams...
1.(1) Find the equation of lines passing through the origin and tangent to the circle having equation x平方+y平方+2倍根下3乘以(x+y)+7=0. (2) Determine the angle enclosed by the tangent lines A. 12cm B. 15cm C. 11cm 相关知识点: ...
Equation of a common tangent to the circlex2+y2−6x=0and the parabolay2=4xis View Solution : View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
The equation of the circle is(x-a)²+(y-b)²=r² The point on the circle is P(M,N). We can write the following formula We can solve for k and f So the slope of the tangent line to this circle is going to be minus one over k ...
题目Find the equation of a circle whose center lies on the linex+4=0, and is tangent to the y‑axis at (0,−2). 相关知识点: 试题来源: 解析 (x + 4)= + (y + 2)= = 16(x + 4)= + (y + 2)= = 16 反馈 收藏
...-...The point Q also lies on the circle and PQ is parallel to the x-axis.(c)Write down the coordinates of Q.[2]nn The tangents to the circle at P and Q meet at T.(d) Find the coordinates of T.[3] ó ó 相关知识点: 试题来源: 解析11(a) ExpresSaS(x-4)^2+(...
is 3y+4x+31=0.[3]The point Q, which lies on the circle, is the same distance from the y-axis as the point P.(iii) Find the equation of the tangent to the circle at Q.[4]The tangents to the circle at P and Q intersect at the point R.(iv) Find the coordinates of R...