(2)ⅱ -5x+3y+12z=12 (3)ⅱ -y+z=3 {many vector forms exist} 反馈 收藏
Find the equation of the plane: (1)with normal vector (bmatrix)2 -1 3(bmatrix) and through (-1,2,4) (2)perpendicular to the line through (2, 3, 1) and (5, 7, 2) and through (3)perpendicular to the line connecting (1,4, 2) and (4, 1, -4) and containing such that...
In this explainer, we will learn how to find the equation of a straight line in vector form. There are many different ways to represent a straight line in the plane. In fact, each of these different representations can be useful for different situations. For example, we recall that if we...
The normal vectors of two parallel planes are equal or have their coordinates in proportion. Answer and Explanation: Given: Consider the plane passing through (−9,2,4) and parallel to plane 6x−6y+4z=0. The vector....
Find the vector equation of the plane passing through the point hati + hatj -2hatk and hati + 2hatj + hatk, 2hati - hatj + hatk.
百度试题 结果1 题目(1) Find the vector equation of a plane which is at 42 unit distance from the origin and which is normal to the vector 2i+ j-2k. 相关知识点: 试题来源: 解析 ·(2i+j-2k)=126 反馈 收藏
Find the vector equation of a plane which is at a distance of 7 units from the origin and normal to the vector 3ˆi+5ˆj−6ˆk. A6√70 B5√70 C8√70 D7√70Submit Find the vector equation of a plane which is at a distance of 6 units from the origin and has 2, -1, ...
Point-normal form of the equation of a plane If you know the coordinates of the point on the plane M(x0,y0,z0) and the surface normal vector of planen={A; B; C}, then the equation of the plane can be obtained using the following formula. ...
Answer to: Find the equation for the plane through the points A(-1, 2, 3), B(2, -3, 1), and C(0, 2, -1). (Simplify your answer in the form ax + by...
The general equation of a plane in space has the following equation: Ax+By+Cz+D=0, where the normal vector to the plane is the vector composed of the terms A, B and C (n→=(A,B,C)). If the plane passes through the origin of coordinates then the gener...