结果1 题目 The equation of the curve whose slope at point (x,y) is x^2-2 and which contains the point (1,-3) is ( ) A. y= 13x^3-2x B. y=2x-1 C. y= 13x^3- (10)3 D. y= 13x^3-2x- 43 相关知识点: 试题来源: 解析 D 反馈 收藏 ...
=k/(1+2x) and find the are a bounded by the curve1+2x y=k/(1+2x) , the line x = 2 and the normal to the curve at the point where x = 0.giving your answer in exact form in terms of k.[5](ii) For k≠0, the gradient at the point on the curve where x = k ...
a15. If the equation for a demand curve is Q = 100 – 2P, its inverse demand curve is given by the equation 15. 如果等式为需求曲线是Q = 100 -,它的相反需求曲线等式给2P[translate]
Answer to: 1. Find an equation for the level curve of the given function for c=\frac{1}{2} and sketch the level curve: f(x, y) = \frac{x}{x^2...
Step 7: Determine the functionThus, we can write:f(x)=kxSince we are looking for a function that passes through the point (1,2):f(1)=2⟹k1=2⟹k=2Therefore, the equation of the curve is:f(x)=2x Step 8: Final equationThe final equation of the curve is:xy=2 Show More |...
11 The equation of a curve is y=-ln(3-ax) , where a is a constant.(i) Find the value of a if the gradient of the curve at y=-In 5 is 2.[4] (ii) Find the value of a if the normal to the curve at x = 1 is parallel to the line 2x-y=5.[2] (i) In the case...
The equation of a curve is given parametrically by _ ,The equation of a curve is given parametrically by _ ,The equation of a curve is given parametrically by _ , 相关知识点: 试题来源: 解析 Equation of tangen ta tA isy=x-π+4。 Equation o ftangen ta tB i sy =-x +3π+4。
Suppose a curve is defined by the equation {eq}\frac{y}{y-x}=x^2-1 {/eq}. Find {eq}\frac{dx}{dy} {/eq}. Implicit Differentiation: Implicit differentiation allows us to take the derivative of a function in which {eq}y {/eq} is not isolated. To take this ty...
For the equation 5 \sqrt{x} -7 \sqrt{y} = 15, Use implicit differentiation to find dy/dx. Find the slope of the curve at the point (16, 1). The slope at each point (x, y) on a curve y = f(x) is given by f'(x) = 1 / ...
Also, find the point of tangency at the given parameter. Answer and Explanation:1 To find the tangent line to any curve(x,y)=(x(t),y(t), we find its slope which isdy/dxor {eq}\; ... Learn more about this topic: Tangent Line |...