The equation of the circle that pass coordinate origin and two intersected points ofi ■■ : 一,and 丁-.「一二.;.——i ..」:一。is.(英汉小词典: equation 方程;coordinate origin 坐标原点) 相关知识点: 试题来源: 解析 答案: 5x2 5 y 2 8x 16 y 0 .译文:过两圆 x 2 y 2 4和x 2 ...
1The equation of the circle C is x^2+ y^2-12x-34y+225 =0. Denote the centre of C by R.圆C的方程为x^2+y^2-12x-34y+225=0.将C的圆心记为R. 1Write down the coordinates of R.写出R的坐标. 2The equation of the straight line L is 4x+3y+50 =0. It is found that C a...
144 0 26:34 App 307 The Distant between a point and a line 【 点到直线距离】 45 0 21:48 App HW 1.9 Arithmetic Sequence By HXY 44 0 16:00 App 312-1 Equations of Ellipses - Exercise 51 0 17:52 App HW 2.5 Transformation 2 BY LJX ...
【题目】一道有关圆的数学题find the equation of the circle whose centre lies on the line 2r + y -1=0 and which passesthrought the points A(-2,0)and B(5,1) 相关知识点: 试题来源: 解析 【解析】圆心在直线2x+y-1=0且过((-2,0)和B(5,1)根据题意圆心还必然在(-2,0)和B(5,1)...
The equation of the circle that pass coordinate origin and two intersected points ofx2+y2=4 and x2+y2+2x-4y+1=0 is(英汉小词典:equation方程;coordinate origin坐标原点)The equation of the circle that pass coordinate origin and two intersected points of x2+y2=4and x2+y2+2x-4y+1=0...
Solution :(x-4)2+(y-4)2=16or(x-1)2+(y+1)2=1.Method 1 Since the circle is tangent to both axes the center of the circle is on the line 5x-3y=8x=4x=1Solving or x±y=0y=4 Therefore the equation of the circle (x-4)+(y-4)2=16or(x-1)2+(y+1)2=1Method 2 Let th...
the circle passes the origin,we let the equa--|||-tion be x+y+Dx Ey=0.-|||-We know that the circle passes points (a,0),(0,-|||-b).-|||-So a2 Da=0 and 62+Eb=0.-|||-Since a≠0,b≠0,SoD=-a,E=-b.-|||-The equation of the circle is x+y-ax -by =0.优质...
Find the equation of the circle passing through the points (4 3) (-2 -5) and (5 2).我真的对这题完全没辙了.马上考试了.答案 想要做圆方程,首先要找圆心A(4,3) B(-2,-5) C(5,2)过AC的直线为 y=-x+7 ,AC的中点为(4.5,2.5),则AC的中垂线为 y=x-2过BC的直线为 y=x-3,BC的...
百度试题 结果1 题目Y Find the equation of the circle.(-15, 8)×一 相关知识点: 试题来源: 解析 r^2=15^2+8^2=125+64=289 反馈 收藏
COn|5dep=(S_1-6) dcl2 2=(3,-t) let the centr of the circle be at Cith, lay racp-cdia Q ansiderop-cd o?ca? r c(hale) dsstace fir mula 9 Byusinθ (h-5)^2+(k+6)^2=(h-1)^2+(k-2)^2 5h2-wh+25+12+12k+3b=h2-2ht1+k2-4k+4 ic-8h+16k=56h-2k=7(I) MN_...