•Calculatetheempiricalformulaofacompoundcomposedof38.67%C,16.22%H,and45.11%N.•Assume100gso•38.67gCx1molC=3.220moleC12.01gC•16.22gHx1molH=16.09moleH1.01gH•45.11gNx1molN=3.219moleN14.01gN •3.220moleC•16.09moleH•3.219moleN •C3.22H16.09N3.219 Ifwe...
38.67gCx1molC=3.220moleC 12.01gC 16.22gHx1molH=16.09moleH 1.01gH 45.11gNx1molN=3.219moleN 14.01gN 3.220moleC 16.09moleH 3.219moleN C3.22H16.09N3.219 Ifwedivideallofthesebythesmallest oneItwillgiveustheempiricalformula Example Theratiois3.220molC=1molC 3.219molN1molN ...