利用消元法求解每个方程组 1. x-y=1 (1)x+y=3 (2)解 (2)-1×(1)代替(2)，原方程组化为 x-y=1 (1)2y=2 (2)解得y=1代入(1)得x-1=1，x=2，故方程组的解为 x=2，y=1.2. 3x-y=26 (1)-2x-y=-24 (2)解 (2)-(-2/3)×(1)代替(2)，原方程组化为 3x
Use the elimination method to solve the system of equations. Choose the correct ordered pair.$$ 3 y = x - 1 $$$ x - 2 y = 2 $$○ A.(12,5)○ B. (6,2) C. (4,1) D. (10,4) 相关知识点: 试题来源: 解析 $$ 3y=x-1x-2y=2 $$ ∵$$ x-1-3y=0 $$ $$ x-3y-1=...
Use the substitution or elimination method to solve each system of equations. State whether it is an inconsistent system or has infinitely many solutions. If a system has infinitely many solutions, write the solution set with y arbitrary.2x+y+z=3x+2y-z=33x-y+z=5 相关知识点: 试题来源:...
Yes, a system of linear equations of any size can be solved by Gaussian elimination.How To: Given a system of equations, solve with matrices using a calculator Save the augmented matrix as a matrix variable [A],[B],[C],…[A],[B],[C],…. Use the ref( function in the calculat...
We can use Gaussian elimination to solve a system of equations. Row operations are performed on matrices to obtain row-echelon form. To solve a system of equations, write it in augmented matrix form. Perform row operations to obtain row-echelon form. Back-substitute to find the solutions. A...
Answer to: Solve the system of equations using elimination: 4x - 5y = 1, x - 5y = -11. By signing up, you'll get thousands of step-by-step...
1. **方程调整**:将第一个方程 \(2x + 3y = 1\) 乘以 2,得到 \(4x + 6y = 2\)。 2. **消元**:用新方程减去第二个方程 \(4x + 2y = 7\): \[ (4x + 6y) - (4x + 2y) = 2 - 7 \implies 4y = -5 \implies y = -\frac{5}{4} \] 3. **代入求解**:将 \(y = ...
Summarize the steps for using Gaussian elimination to solve a system of linear equations such as: (cases) \ x+y+z=6 2x-y+z=3 x+2y-z=2 (cases) Solving the system is not required. 相关知识点: 试题来源: 解析 Rewrite the system as an augmented matrix anduse row operations to rew...
Cluster Algorithm Integrated with Modification of Gaussian Elimination to Solve a System of Linear EquationsThe data accumulation and their inhomogeneous distribution lead to the issue of large and sparse systems solving in various fields: industrials, emergency management, etc. Complex structure in the ...
To solve a system by elimination, add or subtract the equations of the system in order to "eliminate" one of the variables. Continue this process until only one variable is known. Then, substitute this known variable into the preceding equations to find the remaining variables. What is the ...