这是明显的格式错误，楼主刚学python吧。和C/C++不同，python对于代码块的区分是使用缩进进行区分的(C/C++是使用大括号）这段代码这样改就行了 ...for token in sent1: if token.islower(): print token, 'is a lowercase word' elif token.istitle(): print token, 'is a title word'#...
问Python: elif语句显示"syntaxError:无效语法“EN我开始编写代码，在尝试编写代码时，我在elif语句上出现...
16th Nov 2016, 6:51 PM Jacob Gibson 1 Respuesta Responder + 1 Because the indentation is very important inPython. Working code: a = input() c = input() if str(c) == "lb": b = float(a) // float(0.454) print(str(b) + " kg") elif str(c) == "kg": b = float(a) * ...
elif x3上面一句中ipnum.append有5个(,只有4个右括号),括号不配对
python elif invalid syntax 问题 为什么显示我语法错误,我明明是按照书本上做的啊... 为什么显示我语法错误,我明明是按照书本上做的啊 展开 这是明显的格式错误,楼主刚学python吧。和C/C++不同,python对于代码块的区分是使用缩进进行区分的(C/C++是使用大括号)
第一个print和第二个print后面都少了括号 丢
意外标记'elif‘附近的语法错误 $1" = "boot" ] if [ -f /var/log/boot.log ] echo /var/log/boot.log: command not foundline 8: GetLogfileName.sh: line 15: syntax error near unexpected token `elif' 'etLogfileName.sh 浏览3提问于2013-09-11得票数 2 ...
python elif 语法错误 一直都是 invalid syntax，哪里有错啦？这是什么意思？ f 写错了吗？ 字体不对...
If the test expression is False, the code in the body of the if statement is skipped, and the program continues running from the else statement. The syntax of an if/else statement is always:Python Kopírovať if test_expression: # statement(s) to be run else: # statement(s)...
Die if-else-Anweisung wird im Code genauso verwendet wie in der englischen Sprache. Die Syntax für die if-else-Anweisung lautet: if(condition): Indented statement block for when condition is TRUE else: Indented statement block for when condition is FALSE Quelle: python by Programiz Versuchen wi...