Because of their large ionic radii and relatively low oxidation states rare-earth elements generally form complexes which have high coordination numbers and weak metal-ligand bonds. They are often not suitable
Answer to: Assign oxidation numbers to each of the elements in MnO2. By signing up, you'll get thousands of step-by-step solutions to your homework...
Struggling with Self Assessment... ? Get free crash course Text SolutionGenerated By DoubtnutGPT To assign oxidation numbers to the underlined elements in the compound (N2H5)2SO4, we can follow these steps: Step 1: Break down the compoundThe compound can be expressed as (N2H5)2+SO2−4...
When atoms of the same element combine their oxidation states are taken as zero. The carbon inCH3group is in -3 oxidation state. The carbon inCH2OHgroup is in zero oxidation state. d)C––H3C––OOH H−H∣C∣H−C−O∣∣O−H ...
2. In which pair of species are the oxidation numbers of the d-block elements the same? C□ A $$ \left[ C r ( N H _ { 3 } ) _ { 4 } C l _ { 2 } \right] $$^{+}and[Mn$$ ( H _ { 2 } O ) _ { 6 } ] ^ { 2 + } $$B$$ C r O _ { 4 } ^ { 2 ...
These elements, unlike the transition elements, do not exhibit variable oxidation states, and their valence electrons are only present in their outer shell. All of these elements are solid, have a relatively high density, and are opaque. They have oxidation numbers of +3, ±4, and -3. ...
Group-5 elements are most stable in their maximum oxidation state +5 and, therefore, form pentahalides. Most volatile are the pentafluorides, followed by the pentachlorides and the pentabromides. Besides the pure halides, also the oxyhalides (MOX3) are stable in the gas phase. They should ...
The oxidation numbers of a given reactant can be determined by following arbitrarily set rules. These oxidation numbers are useful in determining whether a chemical reaction is an oxidation-reduction reaction. When we find that the oxidation state of an element changes, an oxidation reduction ...
Write the balanced ionic equation which represents the oxidation of iodine(I−)ion by per-manganate ion in basic medium to give iodine (I) and manganese dioxide(MnO2). View Solution Write notes on Intermolecular forces View Solution निम्नलिखित में रे...
fill-up by electrons, they are more stable. However, with increasing atomic number, the outer shell electron is far from nucleus and it is loosely attached. In addition, electrons in p orbital can move to d orbital in an excited state, which contributes to various oxidation numbers as well...