electric field due to finite line charge at equatorial point electric field due to a line of charge on axis We would be doing all the derivations without Gauss’s Law. At the same time we must be aware of the concept of charge density. Here since the charge is distributed over the line...
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum isB0=510nT. What is the amplitude of the electric field part of the wave? View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Cl...
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