using namespace Eigen; void Calcuc(std::vector<Eigen::Quaterniond> qs) { Eigen::Matrix4d M; M.setZero(); for (size_t i = 0; i < qs.size(); i++) { Eigen::Vector4d q(qs[i].x(), qs[i].y(), qs[i].z(), qs[i].w()); Eigen::Matrix4d Mi= q* q.transpose(); M...
Eigenvalues Eigenvalues are easier to explain with eigenvectors. Suppose we have a square matrixA. This matrix defines a linear transformation, that is, if we multiply any vector by A, we get the new vector that changes direction: . However, there are some vectors for which this transformation...
void CalcMatrixDotForLoop(const vector<vector<double>>& a, const vector<vector<double>>& b) { std::chrono::high_resolution_clock::time_point t1 = std::chrono::high_resolution_clock::now(); if (a[0].size() != b.size()) { cout << "error:" << a.size() << "," << b[0...
根据calcLimit的参数,计算会在前maxIters主要特征目标被提取后结束(这句话有点绕,应该就是提取了前int_max_iter个特征值),另一种结束的情况是:目前特征值同最大特征值的比值降至calcLimit的epsilon值之下。在这个迭代算法终止条件的约束下,于是就产生了nEigen个特征脸(object's eigen vector) 程序后两个参数,一...
14std::cout <<"Doing a += b;"<< std::endl; 15a += b; 16std::cout <<"Now a =\n"<< a << std::endl; 17Vector3d v(1,2,3); 18Vector3d w(1,0,0); 19std::cout <<"-v + w - v =\n"<< -v + w - v << std::endl; 20}...
(1.1) where\Delta _gis the negative Laplace–Beltrami operator,\nabla _gis the gradient,\nuis the outward pointing normal vector field,Fis a force field, and\Gamma _\varepsilon \subset \partial Mis a connected piece of boundary of size\varepsilon >0. We denote the corresponding operator by...
</vector>12 changes: 10 additions & 2 deletions 12 app/src/main/res/menu/activity_main_drawer.xml Original file line numberDiff line numberDiff line change @@ -17,11 +17,18 @@ android:id="@+id/nav_test" android:title="测试" android:visible="false" /> </item> <item android...
We further suppose that the (outwards orientated) unit normal vector field nS:S⟶RN satisfies nS(X):X>0, namely the angle between the normal vector at X and the direction X itself is acute. Let α>1 and define f to be the unique α-homogeneous function on RN×n satisfying S={f=...
For simplicity, let us assume that Ω is bounded and Lipschitz, so that the vector field n is defined almost everywhere in ∂Ω and the boundary traces W1,2(Ω)↪L2(∂Ω) exist. Let α∈R. We understand (1) as a spectral problem for the self-adjoint operator −ΔαΩ in L2...
LetL1:B→Bbe a compact, linear operatorwhich isu0-positive with respect toP.ThenL1has an essentially uniqueeigenvector inP, and the corresponding eigenvalue is simple, positive, andlarger than the absolute value of any other eigenvalue.The last result of this section is proved by Keener and ...