百度试题 结果1 题目Solve for x e^x=-2x ( e^x=-2x) 相关知识点: 试题来源: 解析 Graph each side of the equation. The solution is the x-value of the point of intersection. ( x≈ -0.35173371)反馈 收藏
Subtract ( 8e^(-x)) from both sides of the equation. ( e^x+2-8e^(-x)=0) Rewrite ( e^x) as ( ((e^x))^1). ( (e^x)+2-8e^(-x)=0) Rewrite ( -8e^(-x)) as ( -8((e^x))^(-1)). ( (e^x)+2-8((e^x))^(-1)=0) Substitute ( u) for ( e^x)...
e2x−1=e3(−x)e2x-1=e3(-x) Since thebasesare the same, then twoexpressionsare only equal if theexponentsare also equal. 2x−1=3(−x)2x-1=3(-x) Solve forxx. Tap for more steps... -1by3. 2x-1=-3x Move allcontainingxto the left side of the. ...
What is the quadratic formula of e2x−2ex=1 ? https://socratic.org/questions/what-is-the-quadratic-formula-of-e-2x-2e-x-1 Recognise this as quadratic in ex and hence solve using the quadratic formula to find: x=ln(1+2) Explanation: This is an ... How do I solve for x ...
ex=0.5 Solve for x x=−ln(2)≈−0.693147181 Solve for x (complex solution) x=−ln(2)+i×2πn1 n1∈Z Graph
Solve for x:(1)e^x=2(2)e^x=-2(3)e^x=0(4)e^(2x)=2e^x(5)e^x=e^(-x)(6)e^(2x)-5e^x+6=0(7)e^x+2=3e^(-x)(8)1+12e^(-x)=e^x(9)e^x+e^(-x)=3 相关知识点: 试题来源: 解析 (1)x=ln2 (2)no real solutions (3)no real solutions (4)...
A. x=1, 1-cB. x=1, cC. x=-1, c+1D. x=1, c-1E. none of these 相关知识点: 试题来源: 解析 D We rewrite the given equation as x^2-xc+(c-1)=0.Using the quadratic formula, x=(c±√(c^2-4(c-1)))2=(c±(c-2))2=c-1, 1....
Solve for x: 3e(x+2)=21 Equations: In the equation given in this question, we have the mathematical constant e. When solving such equations, we have to either substitute e with its value or directly use a calculator which has an option to input the constant e. Answer and Explanation:...
x2=ex is not the same equation as x=ex, as there are two solutions to every square root, as both negative and positive answers are valid solutions. A way to solve this problem ... sqrt(e(−2x)) https://www.tiger-algebra.com/drill/sqrt(e~(-2x))/ sqrt(e(-2x)) Simplified Roo...
for i in [x for x in range(bn) if x !=inum]: r = d[i][jnum] d[i] -= r * d[inum] def solve(): flag = True while flag: if max(list(d[0][:-1])) <= 0: #直至所有系数小于等于0 flag = False else: pivot() ...