If I notice that the blog is liked by many of you, I will continue writing such as These blogs and on various topics such as Graph and Tree+25 OmarNabill 3 years ago 12 Comments (3) Show archived | Write comment? SilverSurge 3 years ago, # | 0 I have just started ...
It is my "blog" on codeforces, not a forum. So I can write whatever I feel like (keeping it as close to programming as possible). ;) I have been reading about Dynamic Programming (DP) lately. I think I've finally got the gist of it. DP isn't an algorithm that you can apply ...
My solutions for different online judges: UVa, LightOJ, SPOJ, Codeforces, Codechef, Atcoder, Timus, URI etc. java math cpp geometry array stl competitive-programming sort acm-icpc graph-theory adhoc acm programming-contests binary-search number-theory string-processing dynamicprogramming Updated Fe...
Last commit message Last commit date Latest commit subodhk01 Update README.md Oct 4, 2024 f0cd742·Oct 4, 2024 History 73 Commits codeforces add gaa meta tag Jun 17, 2024 main add gaa meta tag Jun 17, 2024 static Add buy me a coffee button ...
December 29, 2013No Commentsalgorithms,c / c++,code,codeforces,dynamic programming,implementation,math,programming languages The problem is from Codeforces: [submit your solution here] The number of trailing zeros can be computed by checking the number of divisors (2 and 5) for all numbers. The ...
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dynamic programming By cniks117, 12 years ago, how can we print all possible subsequences of string using dynamic programming. for ex . for sequence 1,2,3 the possible subsequences are {1},{2},{3},{1,2},{1,3},{2,3},{1,2,3}...
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but I've seen the USACO TEXT about Dynamic Programming, that it used this pseudocode for this problem:# the tail of the second sequence is empty 1 for element = 1 to length1 2 length[element, length2+1] = 0 # the tail of the first sequence has one element 3 matchelem = 0 4 for...
Dynamic Programming How to solve this problem: i was tying to do with 1-d dp!! how to do with 2-d dp??(is it like Matrix chain multiplication) help me plzz!!