令z=y+10x+10则y=z-10x-10，y'=z'-10代入y'=y+10x得：z'=z该方程的通解为：z=C*e^{x}从而得：y=z-10x-10=C*e^{x}-10x-10
解析 y=10x (dy) (dx)= (y+△ y) (x+△ x)= (10+10△ x) (x+△ x)=10 (dy) (dx)|_(x=-1)=10结果一 题目 设y=10x,试按定义求dy/dx|x=-1 答案 y=10xdy y+△y 10+10△x 10 dx x+△x x+△xdy 10 dx x=-1相关推荐 1设y=10x,试按定义求dy/dx|x=-1 ...
求下列微分方程的通解(dy)/(dx)=10^(x+y) , 相关知识点: 试题来源: 解析 解(dy)/(dx)=10^x⋅10^y,(dy)/(10^y)=10^xdx , ∫10^(-y)dy=∫10^xdx-C/(ln10),-(10^(-y))/(ln10)=(10x)/(ln10)-C/(ln10) 10x C In10 In10 故 10^x+10^(-y)=C. 反馈 收藏 ...
=44/3。 先对dx积分,再对dy积分 ∬(10x+y)dσ =∫[0,2]dy∫[0,(2-y)](10x+y)dx =∫[0,2]dy(5*x^2+yx)[0,(2-y)] =∫[0,2][5*(2-y)^2+y*(2-y)]dy =2∫[0,2](2y^2-9y+10)dy =2(2/3*y^3-9/2*y^2+10y)[0,2] =2(2/3*2^3-9/2*2/^2+10*2) =44...
f(x)=10x f'(-1)=lim(x→-1)[f(x)-f(-1)]/(x+1)=lim(x→-1)(10x+10)/(x+1)=lim(x→-1)10(x+1)/(x+1)=10
Answer to: Solve: \frac {dy}{dx} by implicit difference 10xy = 2x + 5y ye^x - 10x = y By signing up, you'll get thousands of step-by-step...
dydx10xy10ydy10xdx10ydy10xdx10yln1010xln10cln10c是积分常数10y10xc10x10yc10xy1c10y原方程的通解是10xy1c10y结果一 题目 求方程dy÷dx=10^(x+y)的通解具体步骤? 答案 ∵dy/dx=10^(x+y) ==>10^(-y)*dy=10^x*dx==>∫10^(-y)*dy=∫10^x*dx==>-10^(-y)/ln10=10^x/ln10-C/ln10...
(x) . 代人所求的非齐次线性方程,得 u'(x)=1 ,两边积分,得u(x)=x+c,故所求方 程的通解为 y=e^(-x)(x+c) (c为任意常数) 解法二 因为p(x)=1 q(x)=e^(-x) ,所以由公式得通解为 y=e^(-∫p(x)dx)(∫q(x)e∫p(x)dxdx+c) =e^(-10x)(∫e^(-x)e^(√x)dx+c)=e^...
解：将其变形为e^(2y)dy=(x-5)dx。两边同时积分，∴(1/2)e^(2y)=(1/2)x²-5x+C。又，x=5时，y=ln5，∴C=25。∴e^(2y)=x²-10x+50。∴y=(1/2)ln(x²-10x+50)。供参考。
F)=∫(I.F) Q1(x) dx+c(c is constant of integration) Where I.F(Integrating Factor): e∫p1(x)dxAnswer and Explanation: Given: dydx+y=10xy2dyy2dx+1y=10x Let's assume: {eq}\di...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a...