代码语言:javascript 复制 Given an arrayofintegers,1≤ a[i]≤n(n=sizeofarray),some elements appear twice and others appear once.Find all the elements that appear twiceinthisarray.Could youdoit without extra space andinO(n)runtime?Example:Input:[4,3,2,7,8,2,3,1]Output:[2,3] 存在一个...
2) Remove duplicates using filter and indexOf TheindexOf()method returns the first index at which a given element can be found in the array, or -1 if it is not present. Thefilter()method creates a shallow copy of a portion of a given array, filtered down to just the elements from t...
Remove duplicates elements from an array is a common array task Javascript offers different alternatives to accomplish it. You can use a mix of methods likeArray.filterandArray.indexOfor a more complex method and also more flexible asArray.reduceor just a simpleArray.forEachthat allows you tu ...
1.Create a array store the result. 2.Create a object to store info of no- repeat element. 3.Take out the element of array, and judge whether in the object. If not push into result array. Array.prototype.removeDuplicates =function(){varres =[];varjs ={};for(vari = 0; i <this.l...
There are multiple ways to remove duplicates from an array. The simplest approach (in my opinion) is to use theSetobject which lets you storeunique valuesof any type. In other words,Setwill automatically remove duplicates for us. constnames=['John','Paul','George','Ringo','John'];letuniq...
JavaScript#26:数组--Remove Duplicates from Sorted Array(EASY) 注意红框里的必须有,否则比如nums=[1,1,1],则输出为[1,1],实际应为[1] 以下是jsshell测试文件及结果:
I am using a JavaScript array to store a series of page numbers, which I can store as strings or integers. I am looking for an algorithm to numerically sort the array and remove duplicates. Any suggestions would be appreciated. Rick Quatro TOPICS Scripting ...
我们可以使用ng-repeat指令遍历一个JavaScript数组,当数组中有重复元素的时候,AngularJS会报错: Error: [ngRepeat:dupes] Duplicates in a repeater are not allowed. Use 'track by' expression to specify unique keys. Repeater: user in users, Duplicate key: number:1。下面的代码就会报错: ...
spread the newly created Set into an Array return the array created in step 2 with an implicit arrow function return Performance of a Set-based deduplication/unique function Remy Sharp has a great post called “Reduce spread and the path to unique” on the performance implications of different ...
constarray=[1,1,1,3,3,2,2];// Method 1: Using a Setconstunique=[...newSet(array)];// Method 2: Array.prototype.reduceconstunique=array.reduce((result,element)=>{returnresult.includes(element)?result:[...result,element];},[]);// Method 3: Array.prototype.filterconstunique=array....