leetcode算法: Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Exa...
Find All Duplicates in an Array 找出数组中所有重复项 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 //solution1 /** //references:https://www.cnblogs.com/g...
Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,8,2,3,1] Output: [2...
Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
442. Find All Duplicates in an ArrayMedium Topics Companies Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that ...
442. Find All Duplicates in an Array 题目描述: Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appeartwice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime?
const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = [...yourArray] yourArrayWithoutDuplicates.forEach((item) => { const i = duplicates.indexOf(item) duplicates = duplicates .slice(0, i) .concat(duplicates.slice(i...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
Sometimes you have an array of data and you want to remove all duplicates from the array. In this article, I will show you three ways in which you can do this. 1) Remove duplicates using forEach and includes The Arrayincludes()method determines whether an array includes a certain value ...