Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read o...
类似LeetCode 442. Find All Duplicates in an Array,由于元素是1~n,因此每个元素的值-1(映射到0~n-1)就可以直接当做下标。 classSolution {public:intfindDuplicate(vector<int>&nums) {for(inti=0;i<nums.size();++i){intindex=abs(nums[i])-1;if(nums[index]>0) nums[index]*=-1;elsereturnind...
leetcode 217. Contains Duplicate、219. Contains Duplicate II、220. Contains Duplicate、287. Find the Duplicate Number 、442. Find All Duplicates in an Array 、448. Find All Numbers Disappeared in an Array 后面3个题都是限制在1～n的,所有可以不先排序,可以利用巧方法做。最后两个题几乎一模一样。
[Leetcode] Find the Duplicate Number 找到重复数字 Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the ...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. ...
- There is only one duplicate number in the array, but it could be repeated more than once. 代码如下: publicintfindDuplicate(int[] nums) {if(nums.length >1){intslow = nums[0];intfast = nums[nums[0]];//以下为求两个指针第一次相遇的点while(slow != fast){ ...
题目: Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference ...LeetCode - Find the Duplicate Number 题目Given an array nums containing n + 1 integers where each integer is...
LeetCode Find the Duplicate Number 找重复出现的数(技巧),题意:有一个含有n+1个元素的数组,元素值是在1～n之间的整数,请找出其中出现超过1次的数。(保证仅有1个出现次数是超过1的数)思路:方法一:O(nlogn)。根据鸽笼原理及题意,每次如果&nums,inttar)//是否在
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: ...
题目链接: Find the Duplicate Number : leetcode.com/problems/f 寻找重复数: leetcode-cn.com/problem LeetCode 日更第 73 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满 发布于 2022-03-30 07:57 力扣(LeetCode) 算法 二分查找 赞同1添加评论 分享喜欢收藏申请转载...