POJ2251——Dungeon Master(三维BFS) 和迷宫问题区别不大,相比于POJ1321的棋盘问题,这里的BFS是三维的,即从4个方向变为6个方向。 用上队列的进出操作较为轻松。 #include<iostream>#include<cstdio>#include<cstring>#include<queue>#include<algorithm>usingnamespacestd;charmap[35][35][35];intvis[35][35][...
The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonally and the maze is surrounded by solid rock on all sides. Is an escape possible? If yes, how long w...
Dungeon Master (POJ - 2251)【 三维 BFS 】 题解:三维的bfs,一开始不怎么理解,就找各种题解,首先要懂的在二维平面上的bfs,bfs一般用来求能够到达某一点使经过的图上的点的值尽可能的小或者是给你两个值x,y,问x能否经过x=2*x或者x+=1这两种操作来变成y (Catch That Cow)。 当...
2、解题思路:BFS的三维Maze[][][]应用,其每步存在前后、左右、上下6个方向的选择。 3、注意事项:BFS入队列的条件判断。 4、实现方法: #include<iostream> #include<queue> usingnamespacestd; structPoint { intx,y,z; intstep; }; Point start,end; intdir[6][3]={{-1,0,0},{1,0,0},{0,-1...
POJ 2251 Dungeon Master(BFS + A*) 题意: 3维迷宫,求从起点到终点最少要走的时间,若不能走到,则输出“Trapped!” 思路: 1. 求最短路径首先想到 BFS,本题稍有变化就是在于 3 维迷宫,其实和 2 维迷宫都是一样的; 2. 解法一采用了优先队列 + 估值函数,但是看来时间上并没有优化太多,同样都是 16...
题目链接:http://poj.org/problem?id=2251 题意:在一个地体空间,有L个平面,每个平面R行C列,寻找从S到E的最短时间,有六个方向(上下东南西北)行走;若不能到达E,输出 "Trapped!",‘.'代表路,‘#’代表墙壁。 题解:一道简单的BFS,只要对图遍历一遍就能出结果,具体步骤看代码。
Dungeon Master(poj 2251) Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move ...
POJ-2251 Dungeon Master (BFS模板题) You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move...
POJ P2251 Dungeon Master 题解 深搜,只不过是三维的。 1#include<iostream>2#include<cstring>3#include<cstdio>4#include<algorithm>5usingnamespacestd;6intl,r,c;7intsx,sy,sz;8intex,ey,ez;9intans=99999;10charmap[41][41][41];11intbook[41][41][41]= {0};12intflag=0;13voiddfs(intx,...
int x,y,z,step; };int L,R,C; bool isvisited[31][31][31]; bool place[31][31][31]; coordinate goal; coordinate start; int times; void bfs(); int dir[6][3] = {{0, 0, 1}, {0, 0, -1}, {1, 0, 0}, {-1, 0, 0}, {0, 1, 0}, {0, -1, 0}};int...