Next, solve the second-order differential equation d2ydt2=a2y with the initial conditions y(0)=b and y′(0)=1. Specify the second initial condition by assigning diff(y,t) to Dy and then using Dy(0) == 1. Get syms y(t) a b eqn = diff(y,t,2) == a^2*y; Dy = diff(...
MATLAB Online で開く Ran in: symst k1 k2 M A0 A(t) dA_dt = 1 * (20 - A) - 3 * diff(A,t) == 0; % Solving for A(t) with different initial conditions A_sol_0 = dsolve(dA_dt, A(0) == 0); A_sol_2 = dsolve(dA_dt, A(0) == 2); ...
Open in MATLAB Online You have2differential equations, so you need2initial conditions. Try this: ic = [-.5, k*0.1];% Set Initial Conditions That will not throw the same error, however you could still encounter the warning about an infinite result. (I did not test the integration code ...
Open in MATLAB Online I am trying to solve three second order ODEs with initial conditions. I am using the symbolic toolbox, but the solver returns this warning: "Explicit solution could not be found; implicit solution returned. ". How can I solve this problem? Thanks! ...
i = Y(0) == [16.0746; 12.9888; -5; 0];% Initial conditions odes=diff(Y) == A*Q; [xSol(t), ySol(t), zSol(t), wSol(t)]= dsolve(odes, i); %Display solution at 10^10 display(double(xSol(10^10))); display(double(ySol(10^10))); ...
initial conditions may be specified by equations like y(a)=b or Dy(a)=b where a and b are constants. Maple may be able to accept a more general type of boundary conditions, but since MuPAD is not explicitly stated to handle such specifications, it...
Open in MATLAB Online Ran in: The differential equations are nonlinear, so it is highly unlikely that there is an analytic solution for them. Integrate them numerically instead (using the appropriate initial conditions and time span) —
error [empty sym] using dsolve "Warning:... Learn more about dsolve, sym, miscategorized MATLAB
Next, solve the second-order differential equation d2ydt2=a2y with the initial conditions y(0)=b and y′(0)=1. Specify the second initial condition by assigning diff(y,t) to Dy and then using Dy(0) == 1. Get syms y(t) a b eqn = diff(y,t,2) == a^2*y; Dy = diff(...
Next, solve the second-order differential equation with the initial conditions and . Specify the second initial condition by assigning diff(y,t) to Dy and then using Dy(0) == 1. syms y(t) a b eqn = diff(y,t,2) == a^2*y; Dy = diff(y,t); cond = [y(0)==b, Dy(0)==...