#include<stdio.h>intmain(){inti;floatf;doubled;charc;printf("int的字节大小是:%ld\n",sizeof(i));printf("float的字节大小是:%ld\n",sizeof(f));printf("double的字节大小是:%ld\n",sizeof(d));printf("char的字节大小是:%ld\n",sizeof(c));return0;}运行结果:int的字节大小是:4bytesfloat...
SIZE public static final int SIZE The number of bits used to represent adoublevalue. Since: 1.5 See Also: Constant Field Values BYTES public static final int BYTES The number of bytes used to represent adoublevalue. Since: 1.8 See Also: ...
// sizeof 操作符用于计算变量的字节大小printf("Size of int: %ld bytes\n",sizeof(integerType));printf("Size of float: %ld bytes\n",sizeof(floatType));printf("Size of double: %ld bytes\n",sizeof(doubleType));printf("Size of char: %ld byte\n",sizeof(charType));return0; } 运行结...
floa如果你叫小编,小编没有回头,那唯一的原因可能就是小编哭了。 建表语句中double类型怎么弄create table chooseclass ( class_id varchar(20)not null, student_id...不是用double 用 decimal(size,d) numeric(size,d) 容纳带有小数的数字。 "size" 规定数字的最大位数。"d" 规定小数点右侧的最大位数。
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javaCopy codepublic class DataTypeSizeExample { public static void main(String[] args) { char c = 'a'; int i = 10; long l = 10000000000L; float f = 3.14f; double d = 3.14159; System.out.println("char size: " + Character.BYTES + " bytes"); ...
public static final int BYTES = SIZE / Byte.SIZE; 表示基本类型 double 的 Class 实例 public static final Class<Double> TYPE = (Class<Double>) Class.getPrimitiveClass("double"); 能够表示的最大值只有标准化一种形式,也就是前文提到过的 public static final double MAX_VALUE = 0x1.ffffffffffff...
NaN A constant holding a Not-a-Number (NaN) value of type double. NegativeInfinity A constant holding the negative infinity of type double. PositiveInfinity A constant holding the positive infinity of type double. Size The number of bits used to represent a double value.Properties...
楼上的都不对啊，sizeof里面应该是类型，不是变量。应该是这样：printf("%d",sizeof(double));回答者： _bingri - 四级 2010-3-9 15:33 sizeof(...)里面可以是类型也可以是变量的~~~
charcharType;// sizeof 操作符用于计算变量的字节大小printf("Size of int: %ld bytes\n",sizeof(integerType));printf("Size of float: %ld bytes\n",sizeof(floatType));printf("Size of double: %ld bytes\n",sizeof(doubleType));printf("Size of char: %ld byte\n",sizeof(charType));return...