LeetCode 29. Divide Two Integers Description Given two integers dividend and divisor, divide two integers without using multiplication, division, and mod operator. The integer division should truncate toward zer
int divide(int dividend, intdivisor) { if(divisor == 0)return MAX_INT;//除数为零 if(divisor == -1 && dividend == -2147483648)return MAX_INT;//被除数为int的最小数(-2147483648),除数为-1,此时由于int整数最大只能为2147483647,会溢出 int flag = 1; if(dividend > 0){//计算符号 dividend...
第四章 LeetCode 题解 0001~0099 0001. Two Sum 0002. Add Two Numbers 0003. Longest Substring Without Repeating Characters 0004. Median of Two Sorted Arrays 0005. Longest Palindromic Substring 0006. Zig Zag Conversion 0007. Reverse Integer 0008. String to Integer Atoi 0009. Palindrome Number 0011...
Leetcode 29 :Divide two integers Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT...LeetCode 29 Divide Two Integers Created with Raphaël 2.1.0开始遍历[0,31],查看b是否为2的次幂确认?返回ans=a<<log b结束二分查找区间[a>>(x...
Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator.Return the quotient after dividing dividend by divisor.The integer division should truncate toward zero.Example 1: Input: dividend = 10, divisor = 3 Output: 3...
Leetcode: Divide Two Integers Divide two integers without using multiplication, division and mod operator. Best method(跟discuss vote最高相似):只有一种情况整数除以整数会overflow,那就是Integer.MIN_VALUE除以-1,这种情况特殊分析。 之所以要用long a, b代替dividend和divisor是因为:比如Integer.MAX_VALUE除以...
LeetCode-Divide Two Integers Description: Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero....
[Leetcode] Divide Two Integers 整数整除 Divide Two Integers Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 位操作法 复杂度 时间O(N) 空间 O(1) 思路 我们设想87 / 4,本来应该的得到21余3,那么如果我们把87忽略余数后分解一下,87 ...
leetcode29 Divide Two Integers 题目要求 Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 在不使用乘法,除法和求余操作的情况下,计算两个整数相除的结果。如果溢出了,则返回最大值。
2. 还要考虑一种特殊的corner case: dividend =Integer.MIN_VALUE, divisor = -1, 此时res =Integer.MAX_VALUE +1,所以cast时会出错,要特殊处理. 3. 当以2的幂次方增长时,就用如下方式来写: 1while(){2sum+=sum;3pow+=pow;4} 1. 2.