This calculator solves for any single missing value in the ideal diode I-V equation for a forward-biased PN-junction diode. Parameters are current, saturation current, voltage, temperature, and ideality factor.
A diode is a semiconductor device that allows an on way switch for current. It will enable the flow of current in one direction and restrict the movement in other opposite directions. Diodes are also known as rectifiers as they change the alternating form of current into direct current. Every...
INPUTS : Vsmin = 20 V, Vsmax = 24 V, Vz = 12 V, IL (current through series resistor) = 500 mA OUTPUTS: Zener series resistance = 16 Ohm. zener diode calculator Equation/Formula Following equation or formula is used for zener diode calculator. ...
Equation Formula — IZM=PZM/VZIZM=PZM/VZ Example: If a Zener diode has a voltage of 5.1V and a power rating of 1W, what is the maximum current that can flow through the diode? IZM = 1W/5.1V = 196 mA Application Zener diodes can be used in simple voltage regulator circuits, such ...
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where IDis the current through the diode. As we know from chapter 5, the relationship between the current and the voltage for a diode is: This equation, when the voltageVDis greater than zero, can be approximated by: Putting these two formulae together and considering that the output voltage...
A superconducting diode is an electronic device that conducts supercurrent and exhibits zero resistance primarily for one direction of applied current. Such a dissipationless diode is a desirable unit for constructing electronic circuits with ultralow power consumption. However, realizing a superconducting ...
to the ratio between the on and off currents \(({{{\rm{R}}}=\frac{{I}_{{on}}}{{I}_{{off}}})\), whereas the other is η, which is the slope representing the change in drain current with a bias voltage and can be obtained from the following Schottky diode equation: $${I}...
-v, which is the difference between the built-in potential and the applied potential. as we supply a small amount of voltage, the reduction in the barrier voltage from the above-given formula is very less and thus only a small number of current carriers cross the junction in this case. ...
We assume that the current flows along the x-axis, and we also fully ignore the screening of the field by thin Nb islands. Since ∇ j = 0 and ∇ A = 0, the phase under the island satisfies the equation ∇2φ(x, y) = 0 with the boundary conditions ...