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Differentiate the power series for f(x) = xe^x. Use the result to find the sum of the infinite series: \sum_{n = 0}^{\infty}\frac{n + 1}{n!} Differentiate the power series for ln (1 + x) at x = 0 to obtain a series representation for the function f(x)...
Step 2: Differentiate f(x) and g(x) Now we need to find f′(x) and g′(x). Differentiate g(x): g(x)=√x=x1/2Using the power rule:g′(x)=12x−1/2=12√x Differentiate f(x): To differentiate f(x)=2xcotx, we will use the product rule:f′(x)=ddx(2x)cotx+2xddx(co...
According to this rule, for a differentiable function {eq}f\left( x \right) {/eq}, the derivative of {eq}n {/eq}th power of function is given by {eq}\dfrac{d}{\left[ {f\left( x \right)} \right]^n} = n{\left[ {f\left( x \right)} \right]^{n...
Types of counterfeit Yamaha Professional Audio products, and points in determining authenticity 1. Analog mixers MG Series (MG16XU/MG12XU, MG166CX-USB) MGP Series 2. Power amplifiers P-S Series 3. Other counterfeit products Wireless microphones Counterfeit analog mixers made to resemble...
Since the early diagnosis of lung cancer is very important for treatment, the accurate diagnosis of SPNs has much importance. The aim of this study was to evaluate the discriminant power of dual time point imaging (DTPI) PET/CT in the differentiation of malignant and benign FDG-avid solitary...
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Differentiate the function {eq}f(x)=e^{x}+x^{e} {/eq} Differentiation Strategy: The derivative of the expression of the given type is solved easily with the following two formulas: One is the power rule that is given by: {eq}\frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1} ...
A higher percentage of breast carcinomas, compared to control mastectomy samples, present iron accumulation in stromal inflammatory cells [3]. Tumor-associated macrophages that secrete ferritin and senescent erythrocytes in the microenviroment in breast cancer contribute by providing ...
The first one is the formula of the power rule of derivative and the second is the formula of chain rule of the derivative. Answer and Explanation: Differentiate with respect to {eq}x {/eq}: {eq}\cosh^2 x {/eq}. $$\begin{align} \dfrac{\mathrm{d} }{\mathrm{d} x}\left (...