If n and p are different positive prime numbers, which of the integers n4, p2, and np has (have) exactly 4 positive divisors ?() A.n4only B.p3only C.nponly D.n4andnp E.p3andnp 答案 E [解析] 因为n和p是互不相同的质数,所以根据质因子求解公式可得n4和p3。的因子数分别为4+1=5个和...
Which of the following can be written as the product of two different prime numbers?A. 8 B. 47 C. 49 D. 91 相关知识点: 试题来源: 解析 D 下面哪个数可以被写成两个不同的质数的乘积? 重点单词:Product,乘积;prime number,质数;composite number,合数. 91=7×13,选D....
prime numbers is less than 100. Four of the 5 prime numbers have the same units digit. What is the median of the 5 prime numbers? 相关知识点: 试题来源: 解析 37. 5个不同质数的和是200,每个质数都小于100,其中4个质数具有相同的单位数字,那么质数的中值为多少? 由题4个质数具有相同的单位数字...
There are only 1+5 or 0+6 can get a 6, but both b,c are prime numbers, so its has to be 1+5, and the units digit is a prime number of 5 only has to be 5. So, assuming that b=5, then c2=5066−25=5041, so c=71. Above all, the product of these three primes is ...
If x and y are different prime numbers, each greater than 2, which of the following must be true ?()Ⅰx+y≠91 Ⅱx-y is an even integer. Ⅲ is not an integer. A.条件(1)充分,但条件(2)不充分. B.条件(2)充分,但条件(1)不充分. C.条件(1)和(2)单独都不充分,但条件(1)和条件(...
The number of differentprime numbers that divide 81 is( ). A. 1 B. 2 C. 3 D. 4. 相关知识点: 试题来源: 解析 A. 题目翻译: 81的不同质因数有多少个? 把81分解质因数,81=3×3×3×3,只有质因数3.所以选A,一个质因数.. 反馈 收藏 ...
If the sum of a set of ten different positive prime numbers is an even number, which of the following prime numbers CANNOT be in the set ?() A.2 B.3 C.5 D.7 E.11 相关知识点: 试题来源: 解析 A [解析] 根据本章前一部分的综述,可知偶数个奇数和是偶数。在五个选项中惟一是偶数...
解析 E 若n=pqr,其中p,q,r是3个不同的正质数(positive prime numbers),n有多少个不同的因子,包括1和n 由因子数求解公式可得n=P・q・r当P,q,r。为质数时n的 因子数为(1+1)(1+1)(1+1)=8个。结果一 题目 If n=pqr, where p,q, and r are three different positive prime numbers, how...
How many different prime numbers are factors of 1 million( ). A. oneB. twoC. threeD. ten相关知识点: 试题来源: 解析 B 1 million =106=(2×5)6=26×56. The only primes are 2 and 5. 有多少具不同的质数是一百万的因数( ). A.1 B.2 C.3 D.10 一百万的因数中,质数有2,5, 故...
要找到五个不同素数平均值为整数的最小可能值,需要先找出一些较小的素数,再分析它们的组合情况。 列出较小的素数最小的几个素数为2、3、5、7、11等。分析素数组合求平均值因为要求五个不同素数的平均值为整数,所以这五个素数的和必须是5的倍数。如果选择2、3、5、7、11,它们的和为2+3+5+7+11=5+5+...