Learn how to find all distinct pairs in Python where the difference between the elements is equal to a given value K. Step-by-step guide with examples.
elif os.path.exists(path2) is False: print('not found %s' % (path2)) return 1 if path1.find('.npy') > 0 and path2.find('.npy') > 0: diff(path1, path2) return for f in walk_dir(path2): if f.find('.npy') < 0: continue f1 = os.path.join(path1, f) f2 = os....