代码(Python3) # Definition for a binary tree root. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def pruneTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]: # 如果 ...
代码(Python3) # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def verticalTraversal(self, root: Optional[TreeNode]) -> List[List[int]]: # ...
# 二叉树节点定义classTreeNode:def__init__(self,val):self.val=val self.left=None self.right=None # 二叉树的DFS遍历 defdfs_binary_tree(root):ifroot is None:returnprint(root.val,end=' ')dfs_binary_tree(root.left)dfs_binary_tree(root.right)# 构造二叉树 root=TreeNode(1)root.left=Tree...
# 二叉树的DFS遍历 def dfs_binary_tree(root): if root is None: return print(root.val, end=' ') dfs_binary_tree(root.left) dfs_binary_tree(root.right) # 构造二叉树 root = TreeNode(1) root.left = TreeNode(2) root.right = TreeNode(3) root.left.left = TreeNode(4) root.left.r...
python代码: class TreeNode: def __init__(self, val=0, left=None, right=None): self.val = val self.left = left self.right = right class Solution: def pseudoPalindromicPaths (self, root: TreeNode): self.ass=[0,0,0,0,0,0,0,0,0,0] #计数路径中数字的个数 self.res=0 #记录符...
class TreeNode: def __init__(self, val): self.val = val self.left, self.right = None, None """ class Solution: """ @param: root: The root of the binary search tree. @param: node: insert this node into the binary search tree @return: The root of the new binary search tree....
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right classSolution: defbuildTree(self, preorder:List[int], inorder:List[int])-> Optional[TreeNode]: ...
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def buildTree(self, preorder: List[int], inorder: List[int]) -> Optional[TreeNode]: ...
这里借用来自社区大佬的Python实现, 非常的优雅: leetcode 上也有这三种遍历的题目, 因为不是本文重点,所以就用递归简单实现一下: 144 前序遍历的简单实现 - medium 给定一个二叉树,返回它的 _前序 _遍历。 代码语言:javascript 代码运行次数:0 运行
这里借用来自社区大佬的Python实现, 非常的优雅: leetcode 上也有这三种遍历的题目, 因为不是本文重点,所以就用递归简单实现一下: 144 前序遍历的简单实现 - medium 给定一个二叉树,返回它的 _前序 _遍历。 输入: [1,null,2,3] 1 \ 2 / 3