Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and is placed on an empty block. Once a winning condition is reached, no more moves is allowed. A player who succeeds in placing n ...
[LeetCode] 348. Design Tic-Tac-Toe Assume the following rules are for the tic-tac-toe game on ann x nboard between two players: A move is guaranteed to be valid and is placed on an empty block. Once a winning condition is reached, no more moves are allowed. A player who succeeds i...
[LeetCode]348.DesignTic-Tac-Toe设计井字棋游戏 Design a Tic-tac-toe game that is played between two players on a n x n grid.You may assume the following rules:1. A move is guaranteed to be valid and is placed on an empty block.2. Once a winning condition is reached, no more ...
You need two arrays: int rows[n], int cols[n], plus two variables: diagonal, anti_diagonal. CareerCup上的原题,请参见我之前的博客17.2 Tic Tac Toe。我们首先来O(n2)的解法,这种方法的思路很straightforward,就是建立一个nxn大小的board,其中0表示该位置没有棋子,1表示玩家1放的子,2表示玩家2。那么...
[LeetCode] 348. Design Tic-Tac-Toe Assume the following rules are for the tic-tac-toe game on ann x nboard between two players: A move is guaranteed to be valid and is placed on an empty block. Once a winning condition is reached, no more moves are allowed....
LeetCode "Design Tic-Tac-Toe" We don't have to keep a complete chess board.. just counters! classTicTacToe { vector<int>cntVer; vector<int>cntHor;intcntDiag0;intcntDiag1;int_n;public:/** Initialize your data structure here.*/TicTacToe(intn) {...
和Valid Tic-Tac-Toe类似,用rows[],cols[],diag和rdiag实时记录对应的行,列,对角线当前的值,当变为N时说明取胜。 class TicTacToe { public: vector<int> rows, cols; int diag, rdiag, N; /** Initialize your data structure here. */ TicTacToe(int n): rows(n), cols(n), diag(0), rdiag...
LeetCode 348. Design Tic-Tac-Toe 2019-12-19 12:41 −原题链接在这里:https://leetcode.com/problems/design-tic-tac-toe/ 题目: Design a Tic-tac-toe game that is played between two players on a n x n&nb... Dylan_Java_NYC
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LeetCode Link size 为 n 的棋牌,player1 和 player2 轮流向空处置子,当 row, column or diagonal 有 n 个相同的子,游戏结束,返回胜利的player,否则返回 0. initial implementation classTicTacToe{int[][]board;intsize;publicTicTacToe(intn){size=n;board=newint[n][n];}// if the player wins, retu...