P (V + ∆V) = R (T +1)……… (2) Subtracting equation (1) from equation (2), we get: P∆V = R Thus, At constant pressure work done by one mole of the an ideal gas in expansion when heated through 1oC is equal to R. hence, CP –CV = R Thus...
Derive an expression for each of the following that is, as much as possible, in terms of measurable properties: P, V, T, Cp, and Cv, and their partial derivatives with respect to each other. S can app Find C_P for any substance in terms of V, T, P and S. H...