Differentiate using the Product Rule which states that ( d/(du)[f(u)g(u)]) is ( f(u)d/(du)[g(u)]+g(u)d/(du)[f(u)]) where ( f(u)=u-√u) and ( g(u)=u+√u). ( (u-√u)d/(du)[u+√u]+(u+√u)d/(du)[u-√u]) Differentiate. ( (u-√u)(1+d/(du)...
Differentiate using the Product Rule which states that ( d/(dy)[f(y)g(y)]) is ( f(y)d/(dy)[g(y)]+g(y)d/(dy)[f(y)]) where ( f(y)=e^y) and ( g(y)=y^e).( e^yd/(dy)[y^e]+y^ed/(dy)[e^y])Differentiate using the Power Rule which states that ( d/(dy)...
Differentiate using the Product Rule which states that ( d/(dr)[f(r)g(r)]) is ( f(r)d/(dr)[g(r)]+g(r)d/(dr)[f(r)]) where ( f(r)=(d^2)/(dr^2)) and ( g(r)=π r^2). ( (d^2)/(dr^2)d/(dr)[π r^2]+π r^2d/(dr)[(d^2)/(dr^2)]) Differentiate...
Suppose that {eq}f(x) {/eq} and {eq}g(x) {/eq} are differentiable functions. Their product {eq}f(x)g(x) {/eq} is then differentiable and we can find the derivative using the product rule stated below. {eq}\frac{d}{dx}[f(x)g(x)]=f'(x)g(x...
A。解析:对于函数\(y = uv\)(这里\(u = x^{2}\),\(v=\sin x\)),根据乘积法则\((uv)^\prime = u^\prime v+uv^\prime\)。\(u = x^{2}\)的导数\(u^\prime = 2x\),\(v=\sin x\)的导数\(v^\prime=\cos x\),所以\(y^\prime = 2x\sin x+x^{2}\cos x\)。选项B中...
Differentiate using the Product Rule which states that ( d/(dt)[f(t)g(t)]) is ( f(t)d/(dt)[g(t)]+g(t)d/(dt)[f(t)]) where ( f(t)=t^(20)) and ( g(t)=(ln)(|t|)).( t^(20)d/(dt)[(ln)(|t|)]+(ln)(|t|)d/(dt)[t^(20)])Differentiate using the chain...
Product Rule for Complex Function: When we have a product of trigonometric functions with powers such as {eq}(h(x))^n(g(x))^m {/eq}, then write its first derivative using the product rule. Afterward, apply the chain rule to simplify the derivative of the power of the trigon...
图解微积分:2个函数相乘的复合函数的derivative推导过程(product rule).mp4 图解笔记:线性代数,微积分,PCA的直觉(机器学习的数学基础)_哔哩哔哩 (゜-゜)つロ 干杯~-bilibili p30编辑于 2018-04-12 10:50 内容所属专栏 数学直觉:让路人能用数学聊天的梦想 以深度学习为目标的,数学直觉化课题 订阅专栏 微积分 ...
百度试题 结果1 题目Use the Product Rule to compute the derivative:()()((t^2+1)(t+9))∣_(t=-4) = ___ 相关知识点: 试题来源: 解析 -23 反馈 收藏
Discovering Derivatives and Derivative Rules including Product, Quotient and Chain RuleWildstrom, Susan Schwartz