We consider the initial-boundary-value problem for a non-linear pseudodifferential equation on a segment. We are interested in thecase of a nonanalytic symbol of the pseudodifferential operator K (p)|p|~(1/2).We study traditionally important problems of the theory of non-linear partial ...
The derivative of the square-root function is obtained from first principles as the limit of the difference quotient. Note: In Maple 2018, context-sensitive menus were incorporated into the new Maple Context Panel, located on the right side of the Maple window. If you are using Maple 2018, ...
She has 20 years of experience teaching collegiate mathematics at various institutions.Cite this lesson To find the derivative of the square root of x, the formula used has to have the square root written in a different way. Learn the steps used to find the derivative of the square root of...
Find the derivative of y = {(2 (x^2) - 1)^5} / {square root {x + 1. Find the derivative of y = square root (x^2 - 1) - sec^-1 x. Find the derivative. f(x) = 4 square root of 5x^2 + 7 Find the derivative y = x square root {x^2+1} ...
Here are useful rules to help you work out the derivatives of many functions (with examples below). Note: the little mark ’ means derivative of, and f and g are functions.Common FunctionsFunction Derivative Constant c 0 Line x 1 ax a Square x2 2x Square Root √x (½)x-½ ...
Use ( √[n](a^x)=a^(x/n)) to rewrite ( √(t^3+1)) as ( ((t^3+1))^(1/2)). ( d/(dt)[((t^3+1))^(1/2)]) Differentiate using the chain rule, which states that ( d/(dt)[f(g(t))]) is ( f()' (g(t))g()' (t)) where ( f(t)=t^(1/2)...
Find the Derivative - d/du 1/( square root of u) ( 1/(√u)) 相关知识点: 试题来源: 解析 Apply basic rules of exponents. ( d/(du)[u^(-1/2)]) Differentiate using the Power Rule which states that ( d/(du)[u^n]) is ( nu^(n-1)) where ( n=-1/2). ( -1/2u^(-1...
Find the Derivative Using Product Rule - d/du h(u)=(u- square root of u)(u+ square root of u) ( h(u)=(u-√u)(u+√u)) 相关知识点: 试题来源: 解析 Differentiate using the Product Rule which states that ( d/(du)[f(u)g(u)]) is ( f(u)d/(du)[g(u)]+g(u)d...
By the Sum Rule, the derivative of ( -14w^(-8)+6√w) with respect to ( w) is ( d/(dw)[-14w^(-8)]+d/(dw)[6√w]).( d/(dw)[-14w^(-8)]+d/(dw)[6√w])Evaluate( d/(dw)[-14w^(-8)]).( 112w^(-9)+d/(dw)[6√w])Evaluate( d/(dw)[6√w]).( 112w^...
Answer to: Find the derivative of y = square root x / 5 x + 7. By signing up, you'll get thousands of step-by-step solutions to your homework...