Find the derivative at x = 2of the function f(x) = 3x. 02:04 Evaluate (i) lim(x->0)(sin4x)/(sin2x) (ii) lim(x->0)(tanx)/x 03:42 Find the derivative of f(x) = 10 x. 01:47 Find the derivative of f(x) = 3at x = 0and at x = 3. 01:24 Evaluate: lim(x rar...
Answer to: Determine derivative of sin x 2 . By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can...
Answer to: Compute the derivative of f(x) = sin(x^2). By signing up, you'll get thousands of step-by-step solutions to your homework questions. You...
Find the derivative of y=x72 View Solution Find the derivative of x−32 View Solution Knowledge Check Find the derivative of x2−2 at x=10. A10 B20 C30 D40Submit Find the derivative of sin2x View Solution Find the derivative of f(x)=x2 View Solution Find the derivative of x2...
Derivative of sin x Derivative $f’$ of the function $f(x)=\sin x$ is: \(\forall x \in ]-\infty, +\infty[ , f'(x) = \cos x\) Proof/Demonstration \[\begin{aligned} \frac{\sin (x+h)-\sin x}{h}&= \frac{\sin (x) \cos (h)+\cos (x) \sin (h)-\sin x}{h} ...
A。解析:对于函数\(y = uv\)(这里\(u = x^{2}\),\(v=\sin x\)),根据乘积法则\((uv)^\prime = u^\prime v+uv^\prime\)。\(u = x^{2}\)的导数\(u^\prime = 2x\),\(v=\sin x\)的导数\(v^\prime=\cos x\),所以\(y^\prime = 2x\sin x+x^{2}\cos x\)。选项B中符...
After the NMR and X-ray characterization, they published the coordinates and structure parameters of PD-L1 in the Protein Data Bank complexed with the compound 1a (PDB: 5N2D) and the compound 2a (PDB: 5N2F). Sign in to download hi-res image Figure 7. Crystal structure of 1a/PD-L1 ...
"The derivative of" is also written d dx So d dx sin(x) and sin(x)’ both mean "The derivative of sin(x)"ExamplesExample: what is the derivative of sin(x) ? From the table above it is listed as being cos(x) It can be written as: ddxsin(x) = cos(x) Or: sin(x)’ =...
结果1 题目 The first derivative of the function f is given by f'(x)=sin (x^2). At which of the following values of x does f have a local minimum? () A. 2.507 B. 2.171 C. 1.772 D. 1.253 E. 0 相关知识点: 试题来源: 解析 A 反馈 收藏 ...
dxd((sin(x))x) Apply exponent rule:ab=ebln(a)(sin(x))x=exln(sin(x))=dxd(exln(sin(x))) Apply the chain rule:exln(sin(x))dxd(xln(sin(x))) =exln(sin(x))dxd(xln(sin(x))) dxd(xln(sin(x)))=ln(sin(x))+xcot(x) ...