The derivative of sec^2x is equal to 2 sec^2x tanx. It is mathematically written as d(sec^2x)/dx = 2 sec2x tanx.
Find the derivative ofy=sec(x). Question: Find the derivative ofy=sec(x). Identities and Trigonometric Derivatives: To differentiate a trigonometric function, it is sometimes necessary to redefine it before applying the differentiation theorems. ...
What is the derivative of y = xsec(kx), where k is a constant? What is the derivative of y = (e^(-x^2))(ln(tan x))? In calculus, what is the derivative of x^2 + 2x + 3? What's the derivative of y=400(2)^{x+3}?
The derivative of secx is $$\d{y}{x} secx =secx tanx $$ But if $$x = \frac{\pi}{3}$$, then $$secx = 2 $$ and the derivative of a constant is 0. And $$sec\frac{\pi}{3} tan\frac{\pi}{3}$$ is equal to $$\frac{3}{2}$$ So what is the derivative of $$secx...
of\ function:} \\&\frac{d\left( \frac{-2cos(x)tan(x)}{ln^{2}(sin(x))sin(x)} + \frac{2sec^{2}(x)}{ln(sin(x))} + \frac{2xcos^{2}(x)tan(x)}{ln^{3}(sin(x))sin^{2}(x)} + \frac{xcos^{2}(x)tan(x)}{ln^{2}(sin(x))sin^{2}(x)} + \frac{2xtan(...
205.8.9 Find the derivative of the function $y=\cos(\tan(5t-4))\\$ chain rule $u=\tan(5t-4)$ $\frac{d}{du}\cos{(u)} \frac{d}{dt}\tan{\left(5t-4\right)}\\$ then $-\sin{\left (u \right )}\cdot 5 \sec^{2}{\left (5 t - 4 \right )}\\$ replacing u with...
7. (TaNx) y'=1/ tangent function y= (cosx) ^2 8. (Cotx) y'=-1/ cotangent function y= (SiNx) ^2 9. y= (inverse sine function arcsinx y'=1/ 1-x^2 10.) V arccosine function y= (arccosx) y'=-1/ 1-x^2 11. V arctan function y= (arctanx) y'=1/ (1+x^2) 12...
(sec^{2}(x)(1))ln(x) + \frac{(tan(x))(1)}{(x)})))ln(x) + \frac{({x}^{tan(x)})(1)}{(x)})))}{(x^{6}{x}^{{x}^{tan(x)}})})))}{((x^{6}{x}^{{x}^{tan(x)}})^{{{e}^{x}}^{x}}^{{e}^{x}}})})))}{({(x^{6}{x}^{{x}^{tan(x)}...
y'=1/x'=cos^2y=1/sec^2y=1/1+tan^2x=1/1+x^2 12.y=arccotx x=coty x'=-1/sin^2y y'=1/x'=-sin^2y=-1/csc^2y=-1/1+cot^2y=-1/1+x^2 13.联立: ①(ln(u^v))'=(v * lnu)' ②(ln(u^v))'=ln'(u^v) * (u^v)'=(u^v)' / (u^v) 另外在对双曲函数shx,chx...