Answer to: Prove that the derivative of csc(x) is -csc(x)cot(x) (i.e. f(x) = csc(x) \to f'(x) = -csc(x)cot(x)). By signing up, you'll get thousands...
Consider a function y=f(x) then differentiation is given bydydx=f′(x) Derivative of cscx is ddxcscx=−cscxcotx Derivative of cotx is ddxcotx=−csc2x Chain Rule: Derivative of f(g(x)) is ddxf(g(x))=f′(g(x))g′(x)...
The derivative of tan xThe derivative of cot xThe derivative of sec xThe derivative of csc xTHE DERIVATIVE of sin x is cos x. To prove that, we will use the following identity:sin A − sin B = 2 cos ½(A + B) sin ½(A − B)....
Find the derivative of y = integral_{cos (x)}^{7 x} cos(u^5) du. Find the derivative of y = cot(x) csc(x). Find the derivative of y(x) if x \tan y +y^2 = \frac{y}{x}. Find the derivative of y = (tan x)^{ln x} ...
Find the derivative: y = x^2 e^x Find the derivative: dy/1+sin t = 2e^{-y} cos (t) dt, y(c) = 0. Find the derivative of y = 2e^x(2x + \sin(5^x)) Find the derivative of y = sec x csc x. Find the derivative of f (x) = (2^{4 x}) (3^{4 x}). ...
•csc(x)—cosecant •arcsec(x)—arcsecant •arccsc(x)—arccosecant •arsech(x)—inverse hyperbolic secant •arcsch(x)—inverse hyperbolic cosecant •|x|,abs(x)—absolute value •sqrt(x),root(x)—square root •exp(x)—e to the power of x ...
Find the derivative off(x)=x+1x. View Solution Find the second order derivative off(x)=2cosx+xwith respect to x View Solution View Solution Find the derivative of sinxcosx=x+y with respect to x View Solution Find the derivative of(1+cosx)xwith respect to x. ...
Next, we need to find the derivative of cotx:ddx(cotx)=−csc2xSubstituting this back into our equation gives:dydx=−1√1−cot2x⋅(−csc2x)This simplifies to:dydx=csc2x√1−cot2x Step 4: Simplify the expressionNow, we need to simplify √1−cot2x. We know that:1−cot2x=...
cot^-1 x 4 x 不知道嗎? 本學習集中的詞語(19) C Constant 0 x 1 x^n nx^n-1 e^x e^x a^x a^x ln a log_a x 1/(x ln a) ln x 1 / x sin x cos x cos x - sin x tan x sec^2 x csc x -csc x cot x sec x sec x tan x cot x -csc^2 x sin^-1 x 1/√...
f(x) = csc x f'(x) = -csc x cot x f(x) = cot x f'(x) = -csc^2 x natural log [ f(x) = ln x ] f'(x) = 1/x exponential functions [ f(x) = b^x ] f'(x) = b^x ⋅ ln(b) f(x) = logb (x) f'(x) = 1/(x)ln(b)關於...