百度试题 结果1 题目The derivative of y = sin(x) is ___. A. cos(x) B. -cos(x) C. sin(x) D. -sin(x) 相关知识点: 试题来源: 解析 A。根据求导公式,sin(x)的导数是 cos(x)。选项 B、C、D 都不符合。反馈 收藏
Let us find the derivative of {eq}y = \sec(x) {/eq}. Let's redefine the function as a function of cosine. Thus we have {eq}y = \dfrac{1}{\cos x}... Learn more about this topic: What is the Derivative of 1/cos(x)?
A. cos(x) B. -cos(x) C. sin(x) D. -sin(x) 相关知识点: 试题来源: 解析 A。根据求导公式,sin(x) 的导数是 cos(x)。选项 B 是 cos(x) 的相反数。选项 C 是原函数。选项 D 是 -sin(x),不符合求导结果。反馈 收藏
Derivative of Cos(x) | Definition, Proof & Functions Solving the Derivative of ln(x) Finding Derivatives of Sums, Products, Differences & Quotients Start today. Try it now Math 104: Calculus 16 chapters | 136 lessons | 11 flashcard sets Ch 1. Graphing and Functions Ch 2. Continuity...
Find the derivative of (x^(n)-a^(n))/(x-a) for some constant a. 03:27 Find the derivative of (i) 2x-(3)/(4) (ii) (5x^(3)+3x-1)(x-1) (iii)... Text Solution Find the derivative of cos x from first principle. 03:06 Find the derivative of the following functions: (...
cosec x? Solution Determine the derivative of cosec x. Let,y= cosec x⇒ y = 1sinx⇒ y = (sinx)-1 Use the formula of the chain rule y = f(g(x))⇒dydx = f'(g(x))×g'(x) Now calculate the derivative: dydx=-(sin x)-2×ddx(sin x)⇒ dydx=-cos xsin x×1sin x...
sin(x+y)=80Now, we differentiate both sides with respect to x. Step 2: Apply the chain ruleUsing the chain rule on the left side, we get:ddx(sin(x+y))=ddx(80)The derivative of a constant (80) is 0. So we have:cos(x+y)⋅ddx(x+y)=0 Step 3: Differentiate x+yNow, we...
Find the second derivative of y = (x^2)cos(3x^3). Find the second derivative. y = 8x^{3} - 5x^{2} + 5e^{x} (a) 48x - 10 + 5e^{x} (b) 32x - 10 + 5e^{x} (c) 10x - 48 + 5e^{x} (d) 10x - 32 + 5e^{x} ...
f(x) = \csc x Find the derivative of the function. y= -(\csc x)^{2} (\cos^{-1}(1-x^{2})) Calculate the derivative of the following function. y = \csc e^x Find the derivative of f(x) = \csc (x^3 + 2x) - \tan(x). Find the derivative of y=10e^x csc(x) . ...
A。解析:对于函数\(y = uv\)(这里\(u = x^{2}\),\(v=\sin x\)),根据乘积法则\((uv)^\prime = u^\prime v+uv^\prime\)。\(u = x^{2}\)的导数\(u^\prime = 2x\),\(v=\sin x\)的导数\(v^\prime=\cos x\),所以\(y^\prime = 2x\sin x+x^{2}\cos x\)。选项B中符...