网络释义 1. 向量导数 数学词汇... ... derivative of a distribution 分布导数 derivative of a vector 向量导数 derivative of higher order 高阶导数 ... www.zftrans.com|基于21个网页 例句 释义: 全部,向量导数 更多例句筛选 1. and enlightening to consider the derivative of a vector. 这对研究矢量...
1) derivative of a vector 向量导数 2) Eigenvector derivative 特征向量导数 1. Computation of eigenvector derivatives using a shift-system dynamic flexibility; 系统移频动柔度式与特征向量导数 2. Using matrix iteration methods, the eigenvector derivatives can be iterated directly, solving the singular ...
derivative of a vector 专业释义 <数学>向量导数 大家的讨论 统计常见术语中英对照 术语表:A•Absolute deviation, 绝对离差•Absolute number, 绝对数•Absolute residuals, 绝对残差•Acceleration array, 加速度立体阵•Acceleration in an arbitrary direction, 任意方向上的加速度•Acce... ...
Derivative of a Vector-Valued Function in 2D You are using a browser not supported by the Wolfram Cloud Supported browsers include recent versions of Chrome, Edge, Firefox and Safari. I understand and wish tocontinue anyway »
This article explores the idea of Weyl–Marchaud fractional derivative on the vector-valued fractal interpolation function with function contractivity factors. Initially, the Weyl–Marchaud fractional derivative of a hidden variable fractal interpolation function (HFIF) with function contractivity factors ...
Vector Derivatives: When taking the derivative of a vector, there is not much difference in the actual process of differentiation. That is, the same differentiation formulas applied to scalar functions also apply to vector functions. The way to take the derivative of a vec...
Answer to: Find the derivative of the vector function r(t) = t a \times ( b + t c) , where a = \langle -1,-1,-4\rangle, b = \langle -3,-3,...
Suppose, we have a vector-valued function that is {eq}r(t) = \langle x(t) \, , \, y(t) \, , \, z(t) \rangle {/eq}, then the derivative of the vector function is {eq}r^{'} (t) = \langle x^{'} (t) \, , \, y^{'} (t) \, , \, z^{'}...
A vector derivative of a vector function (53) can be defined by (54) The th derivatives of for , 2, ... are (55) (56) (57) The th row of the triangle of coefficients 1; 1, 1; 2, 4, 1; 6, 18, 9, 1; ... (OEIS A021009) is given by the absolute values...
Find the derivative of the vector function {eq}\vec r(t)= t\vec a\times (\vec b+t\vec c) {/eq}, where {eq}\vec a=\left \langle -2,3,-4 \right \rangle, \vec b=\left \langle -2,-4,-2 \right \rangle, \vec c=\left \langle -2,-2,4...