以下程序运行后,输出结果是 。 #define P 4.5 #define S(x) P*x*x main() { int a=2,b=3; printf(%.1f\n,S(a+b));}A.49.5B.112.5C.18D.24的答案是什么.用刷刷题APP,拍照搜索答疑.刷刷题(shuashuati.com)是专业的大学职业搜题找答案,刷题练习的工具.一键将文档转化为在线题库
[translate] aBusiness mix [translate] aFront office [translate] aDefine the KPIs - financials and non-financials - of your business? (i.e., P&L, costs, provisions, league tables, rankings, key metrics, internal vs. external comparisons, etc.) [translate] ...
R-E-S-P-E-C-T…In the Name of Love: Poetic Reflections on Civil Protest in the U.S. and Sweden misc{8791eafa-f61b-460b-b387-3d812434f9f3, author = {Dance, Lory}, language = {eng}, title = {R-E-S-P-E-C-T…In the Name of Love: Poetic Reflections on Civ......
define PI 3.1415926 int main(){ double r,h,c,s,p,q;scanf("%f%f",r,h);} r和h是double型的,应该是scanf("%f%f",r,h);
define宏都是直接替换的，不会计算后再替换。s(3+5) = p*3+5*3+5 = 9+15+5 =29 若想计算后在替换，需要加上括号：define S(a) P*(a)*(a)
for 'bss' and initialized data sections#endif}core tc4{architecture=TC1V1.6.2;#ifndef__NO_VTCspace_id_offset=500;// add 500 to all space IDs in the architecture definitioncopytable_space=vtc:linear;// use the copy table in the virtual core for 'bss' and initialized dat...
bipolar (BP) disorders and mood stabilizer efficacypsychotropic drugs used in BP disorderslithium mood stabilizer in manic and depressive episodescarbamazepine and valproate - ‘probable’ stabilizerspartial mood stabilizing propertiesSummary This chapter contains sections titled: The definitions of a mood ...
The Name and Location window appears. Enter a name for the project and a name for the main Java class, and then click Finish. The project is created and a Java file containing the code framework appears in the Java Editor. If you did not specify the class name in the wizard, you can...
结果1 题目下列程序运行结果为:( ) #define P 3 #define S(a) P*a*a main() {int ar; ar=S(3+5); printf(”\n%d",ar); } A. 192ﻩﻩ B. 25 C. 29ﻩﻩﻩ D. 27 相关知识点: 试题来源: 解析 C 、 29 反馈 收藏 ...
#define P 3 #define N 4 void fun(int a[M][P],int b[P][N],int c[M][N]) { int i,j,k,s; for([填空(1)] ) { for([填空(2)] ) { s=[填空(3)] ; for(k=0;ks+=[填空(4)] ; c[i][j]=s; } } } int main() ...