I/0,define the operation★as (a★I/0,then thevalue of ((1★2)★I/0(英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值) A.PD=12 B.PD=12 C.0 D.PD=12 答案 I/0★I/0,I/0★2)★3)I/0★3)I/0★3)I/0=0相关...
15. Define a sequence (rn) of real numbers byx_1=20 . x_2=101 and x_n=(x_(n-1)+1)/(x_(n-2)) for n 2. What is r2020? A.20 B. 101 C.(21)/(101) D. E. (61)/(1010) 相关知识点: 试题来源: 解析 CWriting out the first few terms gives the cycle . So ...
【题目】For real numbers a and b, definea Sb=(a-b)^2 ,What is (x-y)^2S (y-x)^2=(())1}。 答案 【解析】【答案】0【解析】翻译一下题目,就是:对于实数a、b,定义 a≤b=(a-b)^2 ,则(x-y)2$(y-x)2=__依定义有(x-y)^2S(y-x)^2=[(x-y)^2-(y-x)^2]^2=0故...
value of ((1★2)★3) is( )(英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值) A. -23 B. -15 C. 12 相关知识点: 试题来源: 解析 C 【分析】按题中所给的新定义的运算,代入数据即可得解. 反馈 收藏
Define real numbers Find: \sum_{n=1}^{\infty} \frac{2+\cos n}{\sqrt{n^3+n^2+3 Which one of these is correct (a)converges because it's terms are smaller than the terms of \sum_{n=1}^{\infty} \frac{3}{n^3} (b)converg ...
value of ((1★2)★3) is (英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值) A. B. C. 0 D. 试题答案 在线课程 C 分析:按题中所给的新定义的运算,代入数据即可得解. 解答:∵(a★b)=, ∴((1★2)★3)
试题来源: 解析 【答案】 0 【解析】 翻译一下题目,就是: 对于实数a、b,定义a＄b=((a-b))^2,则((x-y))^2＄((y-x))^2= 依定义有((x-y))^2＄((y-x))^2=([((x-y))^2-((y-x))^2])^2=0。 故答案为:0。反馈 收藏 ...
For each pair of real numbers a≠b,define the operation★as (a★b)=a+ba−b,then thevalue of ((1★2)★3) is( )(英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值)A.
【题目】For real numbers a and b, defineaSb=(a-b)^2 。What is( |x-y)^2s(y-x) 2?{{1} 相关知识点: 试题来源: 解析 【解析】【答案】0【解析】由定义可知:(x-y)^2s(y-x)^2=[(x-y)^2-(y-x)^2]^2=0故答案为:0。
For real numbers a and b,define ab=\left ( {a-b} \right )^{2}。What is \left ( {x-y} \right )^{2}$$?___ 答案 【答案】0【解析】由定义知$==0。故答案为:0。相关推荐 1For real numbers a and b,define ab=\left ( {a-b} \right )^{2}。What is \left ( {x-...