#define ll long long const int N = 1e5 + 2; int Q,n,m,k,q[N],e[N]; struct P { int t,r; } p[N]; bool vis[N],fir[N]; set<int>st; int main() { scanf("%d %d %d",&n,&m,&k); for(int i = 1; i <= k; ++ i) { scanf("%d",q
const int N =1e5; vector<pair<int,int>>direc={{0,-1},{0,1},{1,0},{-1,0}}; int32_t main(){ int n,m,k; cin>>n>>m>>k; vector<vector<int>>v(n,vector<int>(m)); vector<vector<int>>vis(n,vector<int>(m,0)); ...
constintMAXn=1e5;inta[MAXn+10],b[MAXn+10];我感觉开数组的时候写 +10 更有逻辑。
顺带说一句#define MAXN (100000 + 5)这样不好看啊，const int MAXN = (int) 1e5 + 5;才好看！
n=e("core:widget/url/url.js"),t=e("core:widget/cookie/cookie.js"),r=e("common:widget/util/callNa-config.js"),l=e("common:widget/util/native-util.js"),p=e("core:widget/stat/pbstat.js"),c=navigator.userAgent,s=function(e,a){var o=a.source||"",n=(i.DownBox._getDuToken...
优质解答 从一开始到最后就是一个条件编译命令(C语言预处理命令):#ifndef 宏名语句段#endif作用:如果再此之前没有定义这样的宏名,则编译语句段;即第一行:#ifndef _DFS_BILLSVR_WORKER_H_,如果定义了宏名 DFS_BILLSVR_WOR... 作业帮用户 2017-10-09 举报 ...
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For precursor ions, the selection window was 2.0 m/z, the AGC target was 1e5 (or 50 ms as a maximum injection time) and the resolving power of 17,500 @m/z 200. Normalized collision energy was 25. A dynamic exclusion of 10s was also applied to avoid the redundancy of MS/MS spectra...
#include <iostream>#include<algorithm>usingnamespacestd;constintN = 1e5 +10;intt, n, a[N], b[N];intmain() { cin>>t;while(t--){ cin>>n;for(inti =1;i <= n; ++ i) cin >>a[i]; sort(a+1, a +1+n);ints =1, e = n, k =n;while(s <=e) ...
所以我们可以确定第m - ( n - 1) 个人拿中第n-1条边,该队输。考虑到m - (n-1) 可能大于总人数, 所以结果应该对人数取模。 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 #include <bits/stdc++.h> using namespace std; const int N = 1e5 + 10; int t, k, n, m...