3.(i) For given g∈G, define g:K→ K by pg(x)=g-xg. Since g∈...
well-defined. It is easily verified that p is a homomorphism of groups and that {g∈Na(K)y(g)=id} {g∈N(K)Mx∈K:g-1xrg=x {g∈Na(K)x∈K:gr=xg}=Ca(K) Now, the assertion is a quick consequence of the First Isomorphism Theorem for相关知识点: 试题...