Runtime:28 ms, faster than73.31% of Python3 online submissions for Defanging an IP Address. Memory Usage:14 MB, less than5.10% of Python3 online submissions for Defanging an IP Address. 【解法】 简洁,一句话概括上面的两种解法。 defdefangIPaddr(self, address: str) ->str:returnaddress.repl...
Given a valid (IPv4) IPaddress, return a defanged version of that IP address. Adefanged IP addressreplaces every period"."with"[.]". Example 1: Input:address = "1.1.1.1"Output:"1[.]1[.]1[.]1" Example 2: Input:address = "255.100.50.0"Output:"255[.]100[.]50[.]0" Constraints...
A defanged IP address replaces every period “.” with “[.]”. Example 1: Input: address = &ldqu...【LeetCode】1108.Defanging an IP Address 方法一:直接在“.”前后插入“[ ]”,记得要变换index 用到了insert函数: 插入单个字符: 插入多个字符: 方法二:重新构建一个string 用到了string的“...
输入:address ="1.1.1.1" 输出:"1[.]1[.]1[.]1" 输入:address ="255.100.50.0" 输出:"255[.]100[.]50[.]0" 注意: 给定地址是有效的IPv4地址。 02 第一种解法 题目的意思是将字符串中的"."替换成"[.]",直接使用replace方法即可。 publicStringdefangIPaddr(String address){returnaddress.replace("...
题目标签:String 题目给了我们一组 ip address,让我们把 . 变成 [.],这题可以用replace,但是这样做的话,好像没意义了。所以还是走一下array,具体看code。 Java Solution: Runtime: 0 ms, faster than 100 % Memory
#1108 Defanging an IP Address Given a valid (IPv4) IPaddress, return a defanged version of that IP address. Adefanged IP addressreplaces every period"."with"[.]". Example 1: Input: address = "1.1.1.1" Output: "1[.]1[.]1[.]1"...