dfs def dfs(maze_mat,routes,p = (0,0)): routes.append(p) if((p[0] == len(maze_mat)-1)and(p[1]==len(maze_mat[0])-1)): return True if((p[0] < 0) or (p[1] < 0) or (p[0] >= len(maze_mat)) or (p[1]>=len(maze_mat[0])) or (maze_mat[p[0]][p[1]...
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https://pan.baidu.com/s/10MJItzUZxqTIB4IvG4-pCg 提取码:2b78 试卷和解析来自"书辰英语"公众号,特此感谢! 答案汇总:听力1-5 CBCAB6-10 BABAA11-15 CABCC16-20 ABACB传统阅读21-23 ADD24-27 CDBA28-31 BDCA32-35 BCDA7选5阅读36-40AEGFD...
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