Example 7: Finding Increasing and Decreasing Intervals on a Graph Given the function p(t)p(t) in the graph below, identify the intervals on which the function appears to be increasing. Figure 6 Solution We see that the function is not constant on any interval...
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right of these values to determine if the derivative is positive or negative. Iff′(x)> 0, thenfis increasing on the interval, and iff′(x)< 0, thenfis decreasing on the interval. This and other information may be used to show a reasonably accurate sketch of the graph of the function...
I've been through a problem like this, the difference was that the graph didn't reduce, but increased. I solved it by inserting a container on the chart's canvas, it had something to do with the size (width and height) of the chart. ...
Given $$k\\ge 2$$ k 鈮2 and $$g\\ge 3$$ g 鈮3 , $$(k,g)$$ ( k , g ) -graphs of infinitely many orders are known to exist and the problem of finding a (k, g)-graph of the smallest possible order is known as the Cage Problem. The aim of our paper is to develop...
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1. The graph below shows the relationship between a car’s value and time. Match each part of the graph (A–C) to its verbal description. Explain the reasoning behind your choice. i. The value of the car holds steady due to a positive consumer report on the same model. ...
A function is decreasing if y decreases as x increases. This means that the function's curve or line goes down on the graph as you move from left to right. There are various ways to tell if a function is decreasing. One method we can use is graphing...
1.state the intervals on which each function is increasing,decreasing or constant2.find a formula to stretch the graph vertically by a factor of 23.find a formula to compress the graph of f(x)=x vertically by a factor of 2 followed by a reflection about the x-axis 相关知识点: 试题...
The red graph is denoted by f(x) = 3xand the green graph is denoted by g(x) = 3x+1. When x is Increasing, f(x) is also Increasing. Hence, g(x) = 3x+1 = 3 . 3x = 3 f(x) Hence, g(x) is a Monotonically Increasing Function. ...