In C language, when declaring a struct type, you must not omit the keyword "struct". ( ) A.正确 B.错误 点击查看答案&解析
刷刷题APP(shuashuati.com)是专业的大学生刷题搜题拍题答疑工具,刷刷题提供In C language, when declaring a struct type, you must not omit the keyword
A项,ask “问,询问;要求;需要”;B项,appeal “呼吁,恳求;上诉”;C项,declare “宣布,声明;断言,宣称”;D项,announce “宣布;述说”。根据语境,此处指“政府呼吁每个人要节约用水”,appeal to sb. to do sth. 表示“呼吁某人做某事”,其余选项均不符合题意且不能用于 “___ to sb. to do sth.” ...
百度试题 结果1 题目Have you anything___? A. declare B. declaring C. to declare D. is declared 相关知识点: 试题来源: 解析 C 反馈 收藏
百度试题 题目Do you have anything___?( ) A.declare B.declaring C.to declared D.declared相关知识点: 试题来源: 解析 to declared 反馈 收藏
百度试题 结果1 题目A.symbolizing B.declaring C.announcing D.confirming相关知识点: 试题来源: 解析 答案:A 解析:共三个人,他们坐在了一个四人坐的桌子边,第四个座位则 “象征(symbolize)” 着父亲在现场。反馈 收藏
百度试题 结果1 题目A. greeting B. receiving C. declaring D. showing 相关知识点: 试题来源: 解析 A 反馈 收藏
百度试题 结果1 题目请选择答案 A. saying B. screaming C. declaring D. telling 相关知识点: 试题来源: 解析 B.screaming 反馈 收藏
In C++, the const keyword is used to declare a variable or function parameter as read-only, indicating that its value cannot be modified after initialization. Once a value is assigned to a const variable, it cannot be changed, and any attempt to modify it will result in a compilation error...
my_list=[[1,3],[3,4],[4,6]] if [3,4] in my_list: print("yes present") else: print("Not present") output is here yes presentCollecting matching elements by filtering 🔝 Create a list by filtering matching string only. ...