Ph.h头文件里已经有getPh方法了，直接引用这个头文件就行了 改成：include<stdio.h> include "Ph.h"int main(){ pHin1=7;k1=430.52124;s1=58.88031;a1=-0.01244;b1=7.31111;double m=getPh(1066, 7);printf("%f",m);return 0;} 变量要用extern申明 比如extern double k1;函数不用...
将fp = fopen(...)移动到变量声明下面来 fprintf(fp,"\n")函数第2个参数是格式,不是输出字串 void main(){ } 加一个void声明 此处不允许声明声明错误
“java declaration not allowed here”错误的含义 在Java中,错误信息“declaration not allowed here”意味着编译器在某个不允许声明变量或方法的上下文中遇到了声明。这通常是因为声明的位置不符合Java的语法规则。 可能导致此错误的常见场景 在代码块外部声明变量:Java中所有变量和方法声明都必须在类或方法内部。 在...
else printf("Error!"); } } fprintf(fp,"\n"); fclose(fp); }运行后出现错误,其中前几个是int、float、double数据“declaration is not allowed here”,还有就是function should return a value ,最后一个错误是fprintf(fp,"\n"); 这行出现expected,不知道是怎么回事。我的目的主要是想把结果输出到一...
1、问题描述 由于安装VS15 Preview 5,搞的系统由重新安装一次;在用vscdoe编译go语言时,出现以下问题: # odbc exec: "gcc": executable file not found in %PATH% exit status 2 2、解决方案 2.1 mingw 64 ... 解决Fatal error: Namespace declaration statement has to be the very first statement ...
这个编译错误消息指的是,在 typedef 声明中引入了一个匿名非C兼容类型,编译器为了链接处理给它了一个名字,但它建议添加一个标签名称来显式命名该类型,以便更好地支持 C 语言的兼容性和跨文件链接。 问题原因 在 C++ 中,匿名结构体和匿名联合体是合法的,它们可以在没有
In thedeclaration specifiersof amember declaration, the sequence enumenum-head-name: is always parsed as a part of enumeration declaration: structS{enumE1:int{};enumE1:int{};// error: redeclaration of enumeration,// NOT parsed as a zero-length bit-field of type enum E1};enumE2{e1};void...
_Atomic is not allowed to be applied to an array type, although an array of atomic type is allowed. typedef int A[2]; // _Atomic A a0 = {0}; // Error // _Atomic(A) a1 = {0}; // Error _Atomic int a2[2] = {0}; // OK _Atomic(int) a3[2] = {0}; // OK (...
g++ does complain about the placement of volatile in the third example. But JLBorges did have line 9 mentioning an error, perhaps shouldn't have had "this is fine" on line 10, maybe a copy / paste typo. Also compile with -std=c++20 rather than c++2a. The g++ manual does not seem ...
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