importdatetime dayofweek = datetime.date(2010,6,16).strftime("%A")print(dayofweek)# weekday Monday is 0 and Sunday is 6print("weekday():", datetime.date(2010,6,16).weekday())# isoweekday() Monday is 1 and Sunday is 7print("isoweekday()", datetime.date(2010,6,16).isoweekday(...
print("isoweekday()", datetime.date(2010,6,16).isoweekday()) dayofweek = datetime.datetime.today().strftime("%A") print(dayofweek) print("weekday():", datetime.datetime.today().weekday()) print("isoweekday()", datetime.datetime.today().isoweekday()) Output: Wednesday weekday(): ...
在您的提问中,datetime.now.dayofweek 实际上存在语法错误。在Python的datetime模块中,应该使用datetime.now()函数来获取当前的日期和时间,然后通过这个返回的datetime对象来访问其属性或方法。不过,需要注意的是,datetime对象本身并没有dayofweek这样的直接属性,但是有一个weekday()方法可以用来获取当前日期是星期几,其中星...
dayofweek = datetime.datetime.today().strftime("%A") print(dayofweek) print("weekday():", datetime.datetime.today().weekday()) print("isoweekday()", datetime.datetime.today().isoweekday()) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. Output: Wednesday weekday(): 2...
importdatetime dayofweek=datetime.date(2010,6,16).strftime("%A")print(dayofweek)# weekday Monday is0and Sunday is6print("weekday():",datetime.date(2010,6,16).weekday())#isoweekday()Monday is1and Sunday is7print("isoweekday()",datetime.date(2010,6,16).isoweekday())dayofweek=datetime...
(6)获取星期的函数DAYNAME(d)、DAYOFWEEK(d)和WEEKDAY(d) select dayname(now()),dayofweek(now()),weekday(now()); (7)获取星期的函数WEEK(d)和WEEKOFYEAR(d) select week(now()),weekofyear(now()); (8)获取天数的函数DAYOFYEAR()和DAYOFMONTH() ...
.../返回datetime的日期部分 DATE_ADD (date2 , INTERVAL d_value d_type ) //在date2中加上日期或时间 DATE_FORMAT (datetime...DATEDIFF (date1 ,date2 ) //两个日期差 DAY (date ) //返回日期的天 DAYNAME (date ) //英文星期 DAYOFWEEK (date ) /...datetime ) //年份 DAYOFMONTH(d...
%j 273 dayofweek %a Mon %A Monday %w 1 misc %c Mon Sep 30 07:06:05 2013 %x 09/30/13 %X 07:06:05 DateTime Translator¶ Automatically convert a datetime format from language/library to another. Django Y-m-d H:i:sGo 2006-01-02 15:04:05MomentJS YYYY-MM-DD HH:mm:ssSwift yy...
例如:(time4-time3) > timedelta(minutes=15)其中time4与time3为datetime类型数据 8.获取某日期是星期几使用Pandas.Series.dt.dayofweek方法来实现 例如: time.dayofweek、grouped_data.svrCtime.iloc[0].dayofweek 其中返回值星期一=0 ~ 星期日=6 具体可查看Pandas.Series.dt.dayofweek相关命令...
print(date3.dayofweek) # 6 # 该年第几周 print(date3.weekofyear) # 39 # 该年的第几天 print(date3.dayofyear) # 275 # 当年是否闰年 print(date3.is_leap_year) # True # 当月总天数 print(date3.days_in_month) # 31 # 哪个季度 ...