The DateDiff function in Excel VBA can be used to get the number of days, weeks, months or years between two dates. You can also use the DateDiff function to calculate the time difference between two times.
代码如下： /* dateDiff 方
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Excel日期函数(1):计算两个日期间隔的天数、月数、年数 使用Excel的隐藏函数DateDif,可以快捷实现。如下图所示: 1、计算间隔的年份数量,注意看A6,B6单元格的日期,差一天,就会减少一年,是严格安排对头的日期来计算。 2、下图是计算A2,B2两个单元格中日期相差的月份数。 3、下图是计算A1,B1两个单元格中日期相差...
System.DateTime date2=System.DateTime.Now.AddYears(2); System.Console.Out.WriteLine("Days :"+DateTimeManger.DateDiff (DateTimeManger.DateInterval.Day,date1,date2).ToString()); System.Console.Out.WriteLine("Hours :"+DateTimeManger.DateDiff
DateDif calculates complete years, months, etc. Actually for your sample it'll be 33 years 11 months and some days, return for years is 33. DateDiff checks if you over the year, month, etc. For more simple example, if start date 30 Dec 2018 and end date 10 Jan ...
https://www.linkedin.com/in/excelenthusiasts/ Message 3 of 3 356 Views 0 Reply lbendlin Super User 05-27-2023 07:43 PM Please provide sample data that covers your issue or question completely, in a usable format (not as a screenshot). https://community.fabric.microsoft.com/...
...oddly though this seems to give seems to yield a result of 1 day less than the same calculation in Excel for example (in this case 30 rather than 31). If you are working with time as well then this will just perform integer rounding, but you could leave dayDiff as double to get...
In the VBA Editor, you can type “DateDiff(” to see the syntax for the DateDiff Function: The DateDiff function contains 5 arguments: Interval:Time unit (Days, Months, Years, etc.). Enter as string. (ex. “m” for Month) SettingDescription ...
DateDif returns 0 years (0 years 0 months 11 days) DateDiff returns 1 year (you are over year 2018) , IMHO, they have different logic. DateDif calculates complete years, months, etc. Actually for your sample it'll be 33 years 11 months and some days, return for years is 33. ...