[PHP] laravel data_get函数以及?? ?: 测试用例 当需要从多维数组中获取值,并且进行判空,赋值默认值的时候 可以使用下面的测试用例 代码语言:javascript 复制 $arr=["name"=>"陶士涵","title"=>["sub"=>"测试"],"test"=>null,"desc"=>"","num"=>0,];$name=data_get($arr,"name","a");$sub...
$subTitle=data_get($arr,"title.sub","a"); $mainTitle=data_get($arr,"title.main","a");//如果没有这个key的情况下,默认值起作用,返回string(1) "a"$test=data_get($arr,"test","a");//如果是null的情况下,默认值不起作用,返回null$test2=data_get($arr,"test","a") ??"a";//如果...
$test=data_get($arr,"test","a");//如果是null的情况下,默认值不起作用,返回null $test2=data_get($arr,"test","a") ?? "a";//如果是null的情况下,??可以起作用,返回string(1) "a" $desc=data_get($arr,"desc","a") ?: "a";//如果是""的情况下,?:可以起作用,返回string(1) "a"...
并且进行判空,赋值默认值的时候 可以使用下面的测试用例 $arr=[ "name"=>"陶士涵", ...
Laravel 避免 Trying to get property of non-object 错误的六种方法 [新增第六种 data_get] 在使用链式操作的时候,例如: return$user->avatar->url; 如果$user->avatar 为 null,就会引起 (E_ERROR) Trying to get property 'url' of non-object 错误。
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用过laravel的肯定用过非常方便的data_get() 和data_set() 函数 是不是很方便 这里分享个JavaScript版本 /*** 访问数据* @param {*} data* @param {*} key* @param {*} value*/exportfunctiondataGet(data,key,value){letkeys=key.split('.')for(leti=0,n=keys.length;i<n;i++){letk=keys[i...
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问题出在我的服务器上。我使用laravel & php服务器作为我的后端&它一次只处理一个请求,所以对/...
在你的代码里...$document是laravel的集合。不是文件对象。尝试加载文件,然后调用getAbsolutePath()。